Answer:
E = 450000 x (1 - 0.32) + (-250000) x 0.32 = 226000
Hope this helps!
:)
Answer: 34 degrees
Step-by-step explanation:
The starting temperature was -5 degrees at 5am, and after two hours, the temperature was 34 degrees at 7am. The temperature increased by 39 degrees, how did we get this answer?
You add -5 and 39
-5 + 39 = 34
A tip for adding negatives:
When you get a problem similar to -5 + 39, you can actually flip them around if you need an easier understanding. So it would be 39 - 5. Both equations still equal 34 as long as you keep the values of each number!
Answer:
option c
Step-by-step explanation:
Quadratic function f(x) = ax² + bx +c
Here the the co-efficient of x, that is a tells if the graph is wider or narrower.
1) a < 1 that is if a is decimal less than 1, then the graph is wider.
2) a > 1, then the graph is narrow.
Answer:
x = 13
Step-by-step explanation:
If 221 is divided by 17, 13 is the answer.
A) The answer is 5.
nCr = n! / (r! (n - r)!)
n - number of things to be chosen from
r - number of chosen things
There are five seniors in a class: n = 5
<span>I choose one senior: r = 1
</span>
nCr = n! / (r! (n - r)!)
5C1 = 5! / (1! (5 - 1)!)
= (5 * 4 * 3 * 2 * 1) / (1 * 4!)
= 120 / (4 * 3 * 2 * 1)
= 120 / 24
= 5
b) The answer is 10.
nCr = n! / (r! (n - r)!)
n - number of things to be chosen from
r - number of chosen things
There are five seniors in a class: n = 5
I choose two seniors: r = 2
nCr = n! / (r! (n - r)!)
5C2 = 5! / (2! (5 - 2)!)
= (5 * 4 * 3 * 2 * 1) / ((2 * 1) * 3!)
= 120 / (2 * (3 * 2 * 1))
= 120 / (2 * 6)
= 120 / 12
= 10
c) The answer is 10.
nCr = n! / (r! (n - r)!)
n - number of things to be chosen from
r - number of chosen things
There are five seniors in a class: n = 5
I choose three seniors: r = 3
nCr = n! / (r! (n - r)!)
5C3 = 5! / (3! (5 - 3)!)
= (5 * 4 * 3 * 2 * 1) / ((3 * 2 * 1) * 2!)
= 120 / (6 * (2 * 1))
= 120 / (6 * 2)
= 120 / 12
= 10
d) The answer is 5.
nCr = n! / (r! (n - r)!)
n - number of things to be chosen from
r - number of chosen things
There are five seniors in a class: n = 5
I choose four seniors: r = 4
nCr = n! / (r! (n - r)!)
5C4 = 5! / (4! (5 - 4)!)
= (5 * 4 * 3 * 2 * 1) / ((4 * 3 * 2 * 1) * 1!)
= 120 / (24 * 1)
= 120 / 24
= 5
e) The answer is 1.
nCr = n! / (r! (n - r)!)
n - number of things to be chosen from
r - number of chosen things
There are five seniors in a class: n = 5
I choose five seniors: r = 5
nCr = n! / (r! (n - r)!)
5C5 = 5! / (5! (5 - 5)!)
= (5 * 4 * 3 * 2 * 1) / ((5 * 4 * 3 * 2 * 1) * 1!)
= 120 / (120 * 1)
= 120 / 120
= 1
