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Umnica [9.8K]
3 years ago
13

Please help me with question #6!!!

Mathematics
1 answer:
Bumek [7]3 years ago
4 0
Previous balance:

+ $481,47→ 11/30
- $300,00 → 11/02
- $68,99 → 11 / 10
- $45,00 → 11/15
- $72,75 → 11/17
----------------------------
+ $481,47 - $113,26 =
+ $368,21 

new balance:

+ $481,47→ 11/30
- $300,00 → 11/02
- $\diagup\!\!\!\! 68,\diagup\!\!\!\!99 → 11 / 10 for -$58,99
- $45,00 → 11/15
- $\diagup\!\!\!\! 72,\diagup\!\!\!\!75 → 11/17 for $ 0
-------------------------------------------------------------------------------------
+ $481,47 - $196,01 =
+$285,46 

Answer: 
\boxed{+285,46}
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Putting the value of y in equation (1), we get

3 x  - \frac{6}{20}=3\\\\ 3 x= \frac{66}{20} \\\\ x=\frac{11}{10}

Two linear equation represented in system B is:

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4.   - 2 x - 8 y = -1

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⇒ 20 y = -3

⇒y =\frac{-3}{20}

Putting the value of y in equation (3),we get

-x + \frac{42}{20}=1 \\\\ x=\frac{22}{20}=\frac{11}{10}

As Two system , that is system (A) and System (B) has same solution.

By looking at all the options , i found that Option (D) is correct. The two system will have the same solution because the first equation of System B is obtained by adding the first equation of System A to 2 times the second equation of System A.

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