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Umnica [9.8K]
2 years ago
13

Please help me with question #6!!!

Mathematics
1 answer:
Bumek [7]2 years ago
4 0
Previous balance:

+ $481,47→ 11/30
- $300,00 → 11/02
- $68,99 → 11 / 10
- $45,00 → 11/15
- $72,75 → 11/17
----------------------------
+ $481,47 - $113,26 =
+ $368,21 

new balance:

+ $481,47→ 11/30
- $300,00 → 11/02
- $\diagup\!\!\!\! 68,\diagup\!\!\!\!99 → 11 / 10 for -$58,99
- $45,00 → 11/15
- $\diagup\!\!\!\! 72,\diagup\!\!\!\!75 → 11/17 for $ 0
-------------------------------------------------------------------------------------
+ $481,47 - $196,01 =
+$285,46 

Answer: 
\boxed{+285,46}
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2 years ago
Read 2 more answers
On a class trip to the museum,5/8 of the students saw the dinosaurs and 7/8 of the students saw either the jewelry collection or
inessss [21]

\frac{2}{8} of students only saw jewelry collection

<em><u>Solution:</u></em>

Given that, On a class trip to the museum,5/8 of the students saw the dinosaurs

7/8 of the students saw either the jewelry collection or the dinosaurs

<em><u>To find: Fraction of students only saw jewelry collection</u></em>

From given statement,

Fraction of students saw dinosaur = \frac{5}{8}

Fraction of students saw either the jewelry collection or the dinosaurs = \frac{7}{8}

Therefore,

Fraction of students only saw jewelry collection = Fraction of students saw either the jewelry collection or the dinosaurs - Fraction of students saw dinosaur

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Thus \frac{2}{8} of students only saw jewelry collection

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