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miv72 [106K]
3 years ago
10

Plz solve this if u know plz​

Mathematics
2 answers:
salantis [7]3 years ago
5 0
<h3>Solution:</h3>

{64}^{ -  \frac{1}{3} } ( {64}^{ \frac{1}{3} }  -  {64}^{ \frac{2}{3} } ) \\  {64}^{ \frac{1}{3} -  \frac{1}{3}  }  -  {64}^{ \frac{2}{3}  -  \frac{1}{3} }  \\  {64}^{0}  -  {64}^{ \frac{1}{3} }  \\ 1 -  \sqrt[3]{64}  \\ 1 - 4 \\  - 3

<h3>Answer:</h3>

- 3

Nutka1998 [239]3 years ago
3 0

Answer:

- 3

Step-by-step explanation:

Using the rules of exponents/ radicals

a^{\frac{m}{n} } ⇔ \sqrt[n]{a^{m} }

a^{-m} ⇔ \frac{1}{a^{m} }

Thus

64^{\frac{1}{3} } = \sqrt[3]{64} = 4

64^{-\frac{1}{3} } = \frac{1}{4}

64^{\frac{2}{3} } = \sqrt[3]{64^{2} } = 4² = 16

Substituting values into the given expression

\frac{1}{4} (4 - 16)

= \frac{1}{4} × - 12

= - 3

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