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fredd [130]
3 years ago
5

Which pair of values could NOT be the roots of a quadratic polynomial?

Mathematics
2 answers:
DENIUS [597]3 years ago
7 0

Answer:

Part c

Step-by-step explanation:

In quadratic equations of real coefficients, the complex roots always occur in conjugate bases. It means, if, 2 + 3i is one of the roots and then the second root must be 2 - 3i.

sasho [114]3 years ago
6 0
That’s with be (c) you welcome!!!!
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Please answer 5,6,7. With explanation.
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First you need to know some rules 2 numbers that are the same with coefficients divided : you differentiate those coeff
and multyplied :you sum up them

12x^8/3x^3= 4x^8-3=4x^5

20^2x=20^x*20^x

m^5*m^-7=m^5-7=m^-2







8 0
4 years ago
A scale on a map shows that 1 inch = 25 miles. How many inches on the map represent 100 miles? *
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Answer:

4 inches

Step-by-step explanation:

Every 25 miles the map shows 1 inch
100 miles is equal to 4 x 25 miles, thus 100 miles on the map will be 4 times longer than 1 inch => 4 inches

8 0
2 years ago
You travel from city A to city B and back your trip last five and a half hours and you maintain a speed of 64 miles per hour the
malfutka [58]

Answer:

401 MILES

Step-by-step explanation:

miles from A to B:

64 * 5.5 = 352 miles

miles from A to C:

352 + 49 = 401 miles

3 0
3 years ago
Which of the following statements about the number line is true?
nadya68 [22]
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5 0
3 years ago
Read 2 more answers
Complete the equations so that the solution of the system of equations is (−1, −4). y= ?X−11 6x− ? Y=10
eimsori [14]

Answer:

y = –7x – 11

6x – 4y = 10

Step-by-step explanation:

From the question given above, we obtained:

x = –1

y = –4

y = ?x – 11 ....... (1)

6x – ?y = 10b......... (2)

Let the two unknown be a and b. Thus the above equation becomes:

y = ax – 11 ......... (3)

6x – by = 10 .......(4)

Next, we shall determine the value of 'a' and 'b'. This can be obtained as follow:

For a:

y = ax – 11

x = –1

y = –4

–4 = a(–1) – 11

–4 = –a – 11

Collect like terms

–4 + 11 = –a

7 = –a

Multiply through by –1

a = –7

For b:

6x – by = 10

x = –1

y = –4

6(–1) – b(–4) = 10

–6 + 4b = 10

Collect like terms

4b = 10 + 6

4b = 16

Divide both side by 4

b = 16 / 4

b = 4

Finally, we shall substitute the value of a and be into equation 3 and 4 respectively.

y = ax – 11

a = –7

y = –7x – 11

6x – by = 10

b = 4

6x – 4y = 10

Therefore, the complete equation are:

y = –7x – 11

6x – 4y = 10

8 0
3 years ago
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