(Game Design) Game Freak, the creators of Pokemon, are an example of a(n):
1 answer:
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Answer:
The output is: Your cost is 100
Explanation:
Given
The above code snippet
and
Required
Determine the output of the code
if cost < 70 or cost > 150
The above condition checks if cost is less than 70 or cost is greater than 150
This condition is false because 100 is neither less than 70 nor is it greater than 150
So, the else statement will be executed.
discount = cost
Which means
discount = 100
So, the print instruction will print: Your cost is 100
Answer:
Here is the C++ program.
#include <iostream> //to use input output functions
using namespace std; // to access objects like cin cout
void chessboard(int N){ // function that takes a number N as parameter generates corresponding board
int i, j;
string black = "B"; // B for black squares
string white = "W"; // W for white squares
for(i=1;i<=N;i++){ //iterates through each column of the board
for(j=1;j<=N;j++){ //iterates through each row of the board
if((i+j)%2==0) // if sum of i and j is completely divisible by 2
cout<<black<<" "; //displays B when above if condition is true
else //if (i+j)%2 is not equal to 0
cout<<white<<" "; } // displays W when above if condition is false
cout<<endl; } } //prints the new line
int main(){ //start of the main function
int num; //declares an integer num
cout << "Enter an integer representing the size of the chessboard: "; //prompts user to enter size of chess board
cin >> num; //reads value of num from user
chessboard(num); } //calls chessboard function to display N lines consist of N space-separated characters representing the chessboard pattern
Explanation:
The function works as follows:
Lets say that N = 2
two string variables black and white are declared. The value of black is set to "B" and value of white is set to "W" to return a chessboard pattern in B and W squares.
The outer loop for(i=1;i<=N;i++) iterates through each column of the chess board. The inner loop for(j=1;j<=N;j++) iterates through each row of chess board.
At first iteration of outer loop:
N = 2
outer loop:
i=1
i<=N is true because i=1 and 1<=2
So the program enters the body of the outer for loop. It has an inner for loop:
for(j=1;j<=N;j++)
At first iteration of inner loop:
j = 1
j<=N is true because j=1 and 1<=2
So the program enters the body of the inner for loop. It has an if statement:
if((i+j)%2==0) this statement works as:
if(1+1) % 2 == 0
(1+1 )% 2 takes the mod of 1+1 with 2 which gives the remainder of the division.
2%2 As 2 is completely divisible by 2 so 2%2 == 0
Hence the if condition evaluates to true. So the statement in if part executes:
cout<<black<<" ";
This prints B on the output screen with a space.
B
The value of j is incremented to 1.
j = 2
At second iteration of inner loop:
j = 2
j<=N is true because j=2 and 2=2
So the program enters the body of the inner for loop. It has an if statement:
if((i+j)%2==0) this statement works as:
if(1+2) % 2 == 0
(1+2 )% 2 takes the mod of 1+2 with 2 which gives the remainder of the division.
3%2 As 3 is not completely divisible by 2
Hence the if condition evaluates to false. So the statement in else part executes:
cout<<white<<" ";
This prints W on the output screen with a space.
B W
The value of j is incremented to 1.
j = 3
Now
j<=N is false because j=3 and 3>2
So the loop breaks and program moves to the outer loop to iterate through the next row.
At second iteration of outer loop:
N = 2
outer loop:
i=2
i<=N is true because i=2 and 2 = 2
So the program enters the body of the outer for loop. It has an inner for loop:
for(j=1;j<=N;j++)
At first iteration of inner loop:
j = 1
j<=N is true because j=1 and 1<=2
So the program enters the body of the inner for loop. It has an if statement:
if((i+j)%2==0) this statement works as:
if(2+1) % 2 == 0
(2+1 )% 2 takes the mod of 2+1 with 2 which gives the remainder of the division.
3%2 As 3 is not completely divisible by 2
Hence the if condition evaluates to false. So the statement in else part executes:
cout<<white<<" ";
This prints W on the output screen with a space.
B W
W
The value of j is incremented to 1.
j = 2
At second iteration of inner loop:
j = 2
j<=N is true because j=2 and 2=2
So the program enters the body of the inner for loop. It has an if statement:
if((i+j)%2==0) this statement works as:
if(2+2) % 2 == 0
(2+2 )% 2 takes the mod of 2+2 with 2 which gives the remainder of the division.
4%2 As 4 is completely divisible by 2 so 4%2 == 0
Hence the if condition evaluates to false. So the statement in if part executes:
cout<<black<<" ";
This prints B on the output screen with a space.
B W
W B
The value of j is incremented to 1.
j = 3
Now
j<=N is false because j=3 and 3>2
So the loop breaks and program moves to the outer loop. The value of outer loop variable i is incremented to 1 so i = 3
N = 2
outer loop:
i=3
i<=N is false because i=3 and 3>2
So this outer loop ends.
Now the output of this program is:
B W
W B
Screenshot of this program along with its output is attached.
