Stop capping its 5 points
Given:
(2, 4) and (3, 3) are on the line.
To find:
The equation of line in point slope form.
Solution:
If a line passes through a point 
with slope m, then the point slope form of the line is
(2, 4) and (3, 3) are on the line. So, slope of the line is
The slope of a line is -1 and it passes through (2,4). So, an equation in point slope form is
Therefore, an equation of the line in point slope form is .
Answer:
a) The function is constantly increasing and is never decreasing
b) There is no local maximum or local minimum.
Step-by-step explanation:
To find the intervals of increasing and decreasing, we can start by finding the answers to part b, which is to find the local maximums and minimums. We do this by taking the derivatives of the equation.
f(x) = ln(x^4 + 27)
f'(x) = 1/(x^2 + 27)
Now we take the derivative and solve for zero to find the local max and mins.
f'(x) = 1/(x^2 + 27)
0 = 1/(x^2 + 27)
Since this function can never be equal to one, we know that there are no local maximums or minimums. This also lets us know that this function will constantly be increasing.
The length of a circumference: l=πD
l₁=π×5=5π
l₂=π×15=15π
Then l₂÷l₁=15π÷5π=3 and the answer is B)
