We know that the points at which the parabola intersects the x axis are
(-5,0) and (1,0)
So the extent between these two points would be the base of the triangle
lets find the length of the base using the distance formula
![\sqrt{[(-5-1)^{2}+(0-0)^{2} ]}](https://tex.z-dn.net/?f=%20%5Csqrt%7B%5B%28-5-1%29%5E%7B2%7D%2B%280-0%29%5E%7B2%7D%20%5D%7D%20%20)
the base b=6
We will get the height of the triangle when we put x=0 in the equation
y=a(0+5)(0-1)
y=-5a
so height = -5a (we take +5a since it is the height)
We know that the area of the triangle =
× 6 × (5a) = 12
15a=12
a= 
Go to a website called desmos it’s a graphing calculator and you just type what you want graphed and it shows it
The percent markup would be 40%. 10+40%=14
Hope this helps!
Can u plz mark me as brainliest? I really need it!
You add 8 and 5 so the equation would be 8+5=13
Answer:
it should be 295 - 65 = x
Step-by-step explanation: