Answer:
In 16170 ways the committee can be formed.
Step-by-step explanation:
3 faculty members and 5 students are required to form a committee.
The eligible to serve on the committee are 7 faculty members and 11 students.
If each committee position has the same duties and voting rights.
Then, the number of ways of selecting 3 faculty members out of 7 eligible faculty members is 
.
Again, the number of ways of selecting 5 students out of 11 eligible students is given by 
.
Therefore, in (35 × 462) = 16170 ways the committee can be formed. (Answer)
Answer:
22,950
Step-by-step explanation:
subtract 51,550 and 28,600. 0 - 0 = 0 then 5-0=5 5-6 you can not do so you barrow from the 1. 1 becomes 0 and 5 becomes 15. 15-6=9. 0-8 you can not do so you need to borrow from the 5. 5 becomes 4 and 0 becomes 10. 10-8=2. Finally, 4-2=2. Put is all together and you have 22,950.
Answer:
See explanation
Step-by-step explanation:
Anything that adds up to 12 has to go in the parethese.
48 / 4 = 12
So 1 and 11
2 and 10
3 and 9
4 and 8
5 and 7
or
6 and 6
Answer:
C(w) = 6w + 9
Step-by-step explanation:
Anytime 0 is given somewhere, it should be given close scrutiny. In an equation whose general form is
y = mx + b
0 will determine the y intercept immediately.
So when x = 0, y will equal
y = 0*m + 9
So b = 9
y = mx + 9 Now we need to find m
I should start using your variables.
C(w) = m*w + 9
when w = 3 then C(3) = 27
27= 3m +9
27-9 =3m + 9 -9
18 = 3m
18/3 = 3m/3
x = 6
So the complete equation is
C(w) = 6w + 9
