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svetoff [14.1K]
3 years ago
8

Help!!!!! No weird answers pls

Mathematics
2 answers:
Papessa [141]3 years ago
7 0

open the parenthes. and then after that you'll get 27+12x-15. if you simplify that then you'll get 12x+12

g100num [7]3 years ago
5 0
3*9= 27
3*4x=12x. 27+12x-15
3*-5=-15


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Simplify: 6-8+7-2-8+13
Vikki [24]

Answer:

The answer is 8.

Step-by-step explanation:

6-8+7-2-8+13

= (6 +7 + 13) - (8+2+8)

= 26 - 18

= 8

5 0
3 years ago
1
Nezavi [6.7K]

Answer:

3 ÷ 1/3 = 9

Step-by-step explanation:

= 3 ÷ 1/3

= 3/3 (3/1) ÷ 1/3

= 9/3 × 3/1

= 9/1

= 9

3 0
2 years ago
Which equation is rewritten in vertex form?
Zinaida [17]
(x + 3)^2 + (x + 4)^2 
= x^2 + 6x + 9 + x^2 + 8x + 16
= 2x^2 + 14x + 25
= 2(x^2 + 7x) + 25
= 2[(x + 7/2)^2  - 49/4] + 25
= 2(x + 7/2)^2 - 98/4 + 25
= 2(x + 7/2)^2 + 1/2


Its B

7 0
2 years ago
CALCULUS: For the function whose values are given in the table below, the integral from 0 to 6 of f(x)dx is approximated by a Re
ladessa [460]

The table gives values of <em>f(x)</em> at various <em>x</em> in the interval [0, 6], and you have to use them to approximate the definite integral,

∫₀⁶ <em>f(x)</em> d<em>x</em>

with a left-endpoint sum using 3 intervals of width 2. This means you have to

• split up [0, 6] into 3 subintervals of equal length, namely [0, 2], [2, 4], and [4, 6]

• take the left endpoints of these intervals and the values of <em>f(x)</em> these endpoints, so <em>x</em> ∈ {0, 2, 4} and <em>f(x)</em> ∈ {0, 0.48, 0.84}

• approximate the area under <em>f(x)</em> on [0, 6] with the sum of the areas of rectangles with dimensions 2 × <em>f(x)</em> (that is, width = 2 and height = <em>f(x)</em> for each rectangle)

So the Riemann sum is

∫₀⁶ <em>f(x)</em> d<em>x </em>≈ 2 ∑ <em>f(x)</em>

for <em>x</em> ∈ {0, 2, 4}, which is about

∫₀⁶ <em>f(x)</em> d<em>x </em>≈ 2 (0 + 0.48 + 0.84) = 2.64

making the answer A.

7 0
2 years ago
Round 86.74 to the nearest whole
zlopas [31]

Answer:

87

Step-by-step explanation:

7 0
3 years ago
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