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Lorico [155]
3 years ago
13

Suppose y varies jointly as x and z. Find y when x = –13 and z = 7, if y = 205 when x = –5 and z = –8. Round your answer to the

nearest hundredth, if necessary.
Mathematics
1 answer:
lesya692 [45]3 years ago
3 0

Answer: y = - 466.375

Step-by-step explanation:

y varies jointly as x and z.

This means that y varies directly as x and also varies directly as z.

In order to remove the proportionality symbol, we will introduce a constant of proportionality, k. Therefore,

y = kxz

The next step is to determine the value of k

if y = 205 when x = –5 and z = –8.

we will substitute these values into the equation to determine k.

205 = k × -5 × -8

205 = 40k

k = 205/40 = 5.125

Therefore, the equation becomes

y = 5.125xz

We want to determine y when x = - 13 and z = 7

y = 5.125 × - 13 × 7

y = 5.125 × - 91

y = - 466.375

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maw [93]

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Step-by-step explanation:

7a^3+14a+12+(-6a^3+12a^2-7)

7a^3+14a+12-6a^3+12a^2-7\\a^3+12a^2+14a+5

7 0
3 years ago
Can anyone answer these 4? if so ill give 40 points. please show work!! and no long division please. , thanks!
dolphi86 [110]
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6 0
3 years ago
A bank pays 5% interest compounded annually. What principal will grow to $12,000 in 10 years.
makvit [3.9K]
<h3>Answer: 7366.96 dollars</h3>

========================================================

Use the compound interest formula:

A = P(1+r/n)^(n*t)

where in this case,

A = 12000 = amount after t years

P = unknown = deposited amount we want to solve for

r = 0.05 = the decimal form of 5% interest

n = 1 = refers to the compounding frequency (annual)

t = 10 = number of years

-------

Plug all these values into the equation, then solve for P

A = P(1+r/n)^(n*t)

12000 = P(1+0.05/1)^(1*10)

12000 = P(1.05)^(10)

12000 = P(1.62889462677744)

12000 = 1.62889462677744P

1.62889462677744P = 12000

P = 12000/1.62889462677744

P = 7366.95904248911

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6 0
3 years ago
If f(x) = x 2 + 1 and g(x) = 3x + 1, find [f(2)-g(1)] 2. 1 2 9
arsen [322]
Put the argument value where the variable is, then evaluate.
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For [f(2) - g(1)] you want the difference of the above values.
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8 0
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A 33 gram sample of a substance that's
Mazyrski [523]

9514 1404 393

Answer:

  6.2

Step-by-step explanation:

We presume your "k-value" is the k in the exponential decay term ...

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This is 1/2 when ...

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The half life is about 6.2 time units.

6 0
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