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laila [671]
4 years ago
10

A gardener has 140 feet of fencing to put around a rectangular vegetable garden. The function A(w)= 70w - w^2 gives the garden's

area A (in square feet) for any width w (in feet). Does the gardener have enough fencing for the area of the garden to be 1300ft^2? Determine whether the solution of the equation is real or non-real.
Mathematics
1 answer:
Alexus [3.1K]4 years ago
5 0

The largest area that can be enclosed will be that of a square (140 ft)/4 = 35 ft on a side. Such a square has an area of (35 ft)² = 1225 ft², not enough for the garden to be 1300 ft². This tells us the solution to the equation you're being asked to write is non-real.

_____

Putting the given numbers in the area equation, you have

... 1300 = 70w -w²

Multiplying by -1 and completing the square, we have

... w² -70w +35² = -1300 +35²

... (w -35)² = 1225 -1300 = -75

Taking the square root shows us the solution is non-real.

... w - 35 = ±√(-75) = ±5i√3

... w = 35 ± 5i√3 . . . . . . . . . after adding 35. These are complex solutions.

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kozerog [31]

Answer:

a. 9 ft

b. 90 ° right angled

c. Right angle

d. 90°

e, Right angle

f. Angles on a straight line

g. 18 spots

Step-by-step explanation:

Here we have maximization question;

a. The separation distance of the dividing lines in a parking lot need to be far apart enough as to accommodate a vehicle with room to open the doors, therefore, it should be between 8.5 to 10 ft wide which gives a mean parking space width of approximately 9 ft

b. The angle of lines of the parking lot to the curb that will accommodate the most cars is 90°, because it reduces the width occupied by a car

c. The angle is right angled

d. Since the adjacent angle + calculated angle = angles on a straight line = 180 °

Therefore, adjacent angle = 90°

e. The angle is right angled

f. Angles on a straight line

g. The number of spots will be 162/9 = 18 spots.

8 0
4 years ago
I went to the grocery store the other day and there were no price tags on anything! I bought 3 loaves of bread and 1 milk jug an
Lostsunrise [7]
To solve this problem, set up and solve a system of equations.  The variables b and m will represent a bread loaf and milk jug, respectively:

\left \{ {{3b + m = 9} \atop {b + 2m =5.5}} \right.

I would solve using substitution.  Take one of the equations and set it equal to one of the variables, for example:

3b + m =9 \\ m = 9 -3b

Now, plug this into the other equation for m and solve for b:

b + 2m =5.5 \\ b + 2(9-3b)= 5.5 \\ b + 18 - 6b = 5.5 \\ -5b + 18 = 5.5 \\ -5b = -12.5 \\ b = 2.5

We now know that a loaf of bread costs $2.50.  Plug this value in for b in the first equation and solve for m:

3b + m = 9 \\ 3(2.5) + m = 9 \\ 7.5+m = 9 \\ m = 1.5

One jug of milk costs $1.50 and one loaf of bread costs $2.50.
8 0
3 years ago
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IrinaVladis [17]
The answer your looking for well be A
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4 years ago
Plz help plz help plz help plz help plz help plz help plz help plz help plz help
Kay [80]

Answer:

a)1.41666667 b)705882353 / 1000000000

Step-by-step explanation:

7 0
3 years ago
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