Answer:
a) x = 5
b) x = 4
Step-by-step explanation:
a) 
= 9.5
3x+4 = 9.5(2)
3x = 19-4
x = 15/3
x = 5
b) 
= 5
7+2x = 5(3)
2x = 15-7
x = 8/2
x=4
This problem is a combination of the Poisson distribution and binomial distribution.
First, we need to find the probability of a single student sending less than 6 messages in a day, i.e.
P(X<6)=P(X=0)+P(X=1)+P(X=2)+P(X=3)+P(X=4)+P(X=5)
=0.006738+0.033690+0.084224+0.140374+0.175467+0.175467
= 0.615961
For ALL 20 students to send less than 6 messages, the probability is
P=C(20,20)*0.615961^20*(1-0.615961)^0
=6.18101*10^(-5) or approximately
=0.00006181
Angle between 16 and 18 = 90 + 55 = 145°
3/2 - x = -12
(multiply everything by 2 to get rid of fraction)
3-2x= -24
3+24 = 2x
3/2 + 12 = x
Answer:
D. Rhombus.
Step-by-step explanation:
This will be a quadrilateral with 4 equal sides.
The oppsoite angles will be equal but they will not be 90 degrees as each triangle of the 3 dimensional figure is an equilateral triangle.
Therfore the cross section is a rhombus.
