Answer:
Problem #1) GCF = 5
Problem #2) LCM = 72
Problem #3) GCF = 8
Problem #4) LCM = 45
Problem #5) 12 and 18
Problem #6) 20 and 40
Step-by-step explanation:
Let me know if you want me to explain these by commenting, and i can write an explanation for each problem! Hope this helped!
Since the ratio is 3:4 there are a total of 7 parts. Divide the 581by 7 to find that each part is 83.
Answer:
109
Step-by-step explanation:
Hopw it helps :).
Answer:
Liquid R has a mass of of 1 kg at a temperature of 30°c kept in a refrigerator to freeze . Given the specific heat capacity is 300 J kg-¹ °c-1 and the freezing point is 4°c . Calculate the heat release by liquid R.
Step-by-step explanation:
Liquid R has a mass of of 1 kg at a temperature of 30°c kept in a refrigerator to freeze . Given the specific heat capacity is 300 J kg-¹ °c-1 and the freezing point is 4°c . Calculate the heat release by liquid R.
This is a geometric sequence, so use the formula for the sum of a geometric sequence:
Sum = (a(r^n - 1))/(r - 1)
where a is the first term, -5
r is the common ratio, 5
and n is the number of terms
Thus,
Sum = ((-5)(5^6 - 1))/(5-1) = -19530