How can you use a number line to find the sum of -4 and 6?

Real life example of plane in geometry

Molodets [167]

Answer: piece of paper or a door

Step-by-step explanation:

5 0

3 years ago

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What is the exact value of 112-25425×34

hammer [34]

Answer -864338

Step-by-step explanation:

i used this app photo math it does all the work for you and gives you a step by step on explaining the math problem

3 0

3 years ago

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Consider the following data set. The data were actually collected in pairs, and each row represents a pair.

Anna11 [10]

Answer:

Step-by-step explanation:

Hello!

a.

Using the data sets you have to analyze them as if they are two independent samples.

The hypotheses are:

H₀: μ₁=μ₂

H₁: μ₁≠μ₂

α: 0.05

Assuming that both data sets are from a normal distribution and both population variances, although unknown, are equal, the statistic to use is:

$t=\frac{(X[bar]_1-X[bar]_2)-(Mu_1-Mu_2)}{Sa\sqrt{\frac{1}{n_1} +\frac{1}{n_2} } } ~~t_{n_1+n_2-2}$

$Sa^2= \frac{(n_1-1)S^2_1+(n_2-1)S^2_2}{n_1+n_2-2}$

$Sa^2= \frac{9*5.38+9*3.65}{10+10-2} =4.51$

Sa= 2.12

$t_{H_0}= \frac{(49.69-50.52)-0}{2.12*\sqrt{\frac{1}{10} +\frac{1}{10} } } = -0.875$

The p-value for the two-tailed test is:

P( $t_{18}$ ≤-0.875) + P( $t_{18}$ ≥0.875)= P( $t_{18}$ ≤-0.875) + (1 - P( $t_{18}$ ≤0.875))= 0.1965 + ( 1 - 0.8035)= 0.393

Since there is no significant level I determined it at 5%, comparing it to the p-value, the hypothesis test is not significant. Meaning that the difference between the population means of both groups is equal to zero.

b.

Considering the given data as a paired sample, you have to determine the variable difference to conduct the test:

Xd: the difference between X₁ and X₂

Before the sample mean and sample standard deviation you have to calculate the difference between the observations of group 1 and group 2. (2nd attachment)

Mean X[bar]d= -0.83

Standard deviation Sd= 1.28

The hypotheses for the paired sample test are:

H₀: μd=0

H₁: μd≠0

α: 0.05

$t= \frac{X[bar]d-Mud}{\frac{Sd}{\sqrt{n} } } ~~t_{n-1}$

$t_{H_0}= \frac{-0.83-0}{\frac{1.28}{ \sqrt{10} }} = -2.05$

The p-value for the two-tailed test is:

P( $t_{9}$ ≤-2.05) + P( $t_{9}$ ≥2.05)= P( $t_{9}$ ≤-2.05) + (1 - P( $t_{9}$ ≤2.05))= 0.0353 + (1 - 0.9647)= 0.0706

Comparing the p-value with the significance level, the hypothesis test is not significant. Meaning that the population mean of the difference between group 1 and group 2 is equal to cero. There is no difference between the two groups.

c.

The value of the statistic in "a" is greater than the value of the statistic obtained in "b". Since there are two samples used an "a" the degrees of freedom of the test are the double as the ones used in "b". The p-value obtained in "b" is around half of the p-value of "a".

The main difference is that in "a" you compared two different samples but in "b" you compared two dependent samples when analyzing paired data the "effect of the individual" is removed from the equation.

I hope this helps!

3 0

3 years ago

An amusement park's owners are considering extending the weeks of the year that it is opened. The owners would like to survey 10

uranmaximum [27]

The best way to randomly choose the 100 families would be to allow a random number generator to come up with 100 families within a 50 radius of the amusement park.

Using this method would ensure that it is more randomised & not limited to people who come at a specific time or are in a specific area as well as it not be affected by subconscious bias of people when selecting people to survey.

6 0

3 years ago

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PLS HELP ME GUYS I WILL MARK BRAINLIEST IF YOU SOLVE THE QUESTION

iVinArrow [24]

Answer:

16m

Step-by-step explanation:

4 0

2 years ago