Answer: Required expression:
Result: 
Step-by-step explanation:
Given phrase: 
Required expression:
['+' used to express sum, 'x' used in place of 'of']
Since 18+16 = 34
Then,
![\dfrac14\times(18+16)=\dfrac14\times34 \\\\=\dfrac{1}{2}\times17\ \ \text{[Divide numerator and denominator by 2]}\\\\=\dfrac{17}{2}](https://tex.z-dn.net/?f=%5Cdfrac14%5Ctimes%2818%2B16%29%3D%5Cdfrac14%5Ctimes34%20%20%5C%5C%5C%5C%3D%5Cdfrac%7B1%7D%7B2%7D%5Ctimes17%5C%20%5C%20%5Ctext%7B%5BDivide%20numerator%20and%20denominator%20by%202%5D%7D%5C%5C%5C%5C%3D%5Cdfrac%7B17%7D%7B2%7D)
Hence,
Answer:
its going well hbu
have a good day :)
Step-by-step explanation:
With questions like this (to see if theyre parallel), all you have to do is see if lines have a congruent slope. if yes (ex: 2 and 2), then they are parallel. if the slopes are opposites (ex: 4 and -1/4), then they are perpendicular. If they have no such relation (ex: -3 and 1/7), then they are neither.
with this problem, find the slope by separating the same variable in each equations, like this:
2x + 7y = 6
-2x -2x
7y = -2x + 6
(the second equation is already separated) so now we have
7y = -2x + 6 and 7y = 2x + 6
since -2 does NOT equal 2, these two graphs/lines are NOT parallel.
Hope this helped!
I believe the answer is Associative Property of Addition, I may be wrong. If i am my apologies.
<h3>
Answer: x+3</h3>
==============================================================
Explanation:
Use a graphing tool like Desmos to plot y = |x+3|
See below.
The graph is a V shaped figure. The vertex is at (-3,0). The interval x > 5 is entirely to the right of this vertex. So we only focus on the right hand side of the V shape.
The line making up this right hand side is the equation y = x+3
Therefore, if x > 5 then y = |x+3| becomes y = x+3
In short, we erase the absolute value lines.