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ludmilkaskok [199]
3 years ago
12

Y=100x0.3^x increase or decrease need the answer ASAP

Mathematics
1 answer:
miss Akunina [59]3 years ago
3 0
It would decrease because you are multiplying by a decimal.
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Find y by itself 7y=14x-21
vlada-n [284]

Answer: y=2x-3

Step-by-step explanation:

divide both sides by 7

7y/7=(14x-21)/7

y=2x-3

8 0
3 years ago
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The ratio of Rogers age to his sons is 7:3. If the sum of their ages are 60 how old is Rogers son
Nimfa-mama [501]

Answer:24

Step-by-step explanation:

Sum of their ages is 60 yr. As such

7x + 3x = 60

10x = 60

x = 60 / 10

x = 6

The rationale is 6, therefore

Father's age is 7x = 7 × 6= 42 years

Son's age is 3x = 3 × 6 = 18 years

Difference in their ages

42 - 18 = 24 years

5 0
3 years ago
I GIVE BRAINIEST “What is the solution of a system of equations if the sum of the
zhenek [66]

Answer:

At the bottom!!

Step-by-step explanation:

y=2

2=0+x

x=2

Solution of a system of equations:A system of linear equations contains two or more equations e.g. y=0.5x+2 and y=x-2. The solution of such a system is the ordered pair that is a solution to both equations. ... The solution to the system will be in the point where the two lines intersect.

Hope this helps!!

8 0
3 years ago
PLEASE HELP ME !!! SOS
kramer

Answer:6x - 2y = 22

Step-by-step explanation:

Just multiplying equation by 2

Can do it with any number

8 0
3 years ago
Factor f(x) = 15x^3 - 15x^2 - 90x completely and determine the exact value(s) of the zero(s) and enter them as a comma separated
Illusion [34]

Answer:

x=-2,0,3

Step-by-step explanation:

We have been given a function f(x)=15x^3-15x^2-90x. We are asked to find the zeros of our given function.

To find the zeros of our given function, we will equate our given function by 0 as shown below:

15x^3-15x^2-90x=0

Now, we will factor our equation. We can see that all terms of our equation a common factor that is 15x.

Upon factoring out 15x, we will get:

15x(x^2-x-6)=0

Now, we will split the middle term of our equation into parts, whose sum is -1 and whose product is -6. We know such two numbers are -3\text{ and }2.

15x(x^2-3x+2x-6)=0

15x((x^2-3x)+(2x-6))=0

15x(x(x-3)+2(x-3))=0

15x(x-3)(x+2)=0

Now, we will use zero product property to find the zeros of our given function.

15x=0\text{ (or) }(x-3)=0\text{ (or) }(x+2)=0

15x=0\text{ (or) }x-3=0\text{ (or) }x+2=0

\frac{15x}{15}=\frac{0}{15}\text{ (or) }x-3=0\text{ (or) }x+2=0

x=0\text{ (or) }x=3\text{ (or) }x=-2

Therefore, the zeros of our given function are x=-2,0,3.

7 0
4 years ago
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