Let x be the width of the cardboard (which means the length of the cardboard is x+88), then the dimensions of the box are:
Length = [(x + 88) - 2(33)]
Width = x - 2(33)
Heighth = 33
Volume = length · width · heighth
144,144 = [(x + 88) - 2(33)] · [x - 2(33)] · 33
144,144 = (x+22)(x-66)(33)
4368 = (x+22)(x-66)
4368 = x² - 44x - 1452
0 = x² - 44x - 5820
use the quadratic formula to calculate that x = 101
Answer: cardboard width = 101, cardboard length = 189
Answer:
rate of motorboat: b
rate of current: c
So the rate the boat travels upstream is $b - c$, and the rate it travels downstream is $b + c$
Step-by-step explanation:
d = rt
200 = (b - c)\cdot 5
200 = (b + c)\cdot 4
b - c = 40
b + c = 50
Adding these equations, we get:
2b = 90
b = 45
So
c = 50 - 45 = 5
<u>Therefore the rate of the boat is 45kph, and the rate of the current is 5kph</u>
Hope this helps :)
Hey there! :)
Answer:
h(x) = 3x² - 7x - 6
Step-by-step explanation:
Calculate h(x) by adding the two polynomials:
h(x) = f(x) + g(x):
h(x) = x² - 3x + 5 + 2x² - 4x - 11
Combine like terms:
h(x) = 3x² - 7x - 6
That question probably meant how far are the two distances.
One way to solve this problem is by using the distance formula which you can search up.
and so the answer is d=13. D is distance
