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andrew-mc [135]

2 years ago

11

Simplify each expression

1 answer:

katrin2010 [14]2 years ago

6 0

Answer:

${x}^{ \frac{1}{2} } \times {x}^{ \frac{2}{3} }$

${x}^{ \frac{3 + 4}{6} }$

${x}^{ \frac{7}{6} }$

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If f(x) = x^3 – 10x^2 + 29x – 30 and f(6) = 0, then find all<br> of the zeros of f(x) algebraically.

tino4ka555 [31]

Step 1: 1

(((x3) - (2•5x2)) + 29x) - 30 = 0

Step 2 2.1 x3-10x2+29x-30 is not a perfect cube

Step 3 Factoring: x3-10x2+29x-30

Thoughtfully split the expression at hand into groups, each group having two terms :

Group 1: 29x-30
Group 2: -10x2+x3

Pull out from each group separately :

Group 1: (29x-30) • (1)
Group 2: (x-10) • (x2)

7 0

2 years ago

Can somebody help me on 23 and 24, it’s geometry

Luda [366]

Question 23:

x = 4

DE = 44

Question 24:

x = 25

SE = 28

Step-by-step explanation:

As RS is the perpendicular bisector of DE, it will divide DE in two equal parts DS and SE

<u>Question number 23:</u>

Given

DS = 3x+10

SE = 6x-2

As the two segments are equal:

$DS = SE\\3x+10 = 6x-2$

Subtracting 10 from both sides

$3x+10-10 = 6x-2-10\\3x = 6x-12$

subtracting 6x from both sides

$3x -6x = 6x-6x-12\\-3x = -12$

Dividing both sides by -3

$\frac{-3x}{-3} = \frac{-12}{-3}\\x = 4$

Now

$DS = 3x+10\\= 3(4)+10\\= 12+10\\=22$

And

$SE = 6x-2\\= 6(4)-2\\= 24 - 2\\=22\\DE = DS+SE\\= 22+22\\=44$

<u>Question No 24:</u>

Given

DS = x+3

DE = 56

We know that:

$DS = \frac{1}{2}DE\\x+3 = \frac{56}{2}\\x + 3 = 28\\x = 28-3\\x = 25$

So

DS = $25+3 = 28$

As DS is 28, SE will also be 28

Hence,

Question 23:

x = 4

DE = 44

Question 24:

x = 25

SE = 28

Keywords: Bisector, Line segment

Learn more about line segments at:

#LearnwithBrainly

4 0

2 years ago

The function f(x) is a cubic function and the zeros of f(x) are -6, -3 and 1. The

jarptica [38.1K]

Answer:

$P(x)=-5x^3-40x^2-45x+90$

Step-by-step explanation:

<u>Equation of a Polynomial</u>

Given the roots x1, x2, and x3 of a cubic polynomial, the equation can be written as:

$P(x)=a(x-x1)(x-x2)(x-x3)$

Where a is the leading coefficient.

We know the three roots of the polynomial -6, -3, and 1, thus:

$P(x)=a(x+6)(x+3)(x-1)$

Since the y-intercept of the polynomial is y=90 when x=0:

90=a(0+6)(0+3)(0-1)

90=a(6)(3)(-1)=-18a

Thus

a = 90/(-18) = -5

The polynomial is:

$P(x)=-5(x+6)(x+3)(x-1)$

We must write it in standard form, so we have to multiply all of the factors as follows:

$P(x)=-5(x^2+6x+3x+18)(x-1)$

$P(x)=-5(x^2+9x+18)(x-1)$

$P(x)=-5(x^3-x^2+9x^2-9x+18x-18)$

$P(x)=-5(x^3+8x^2+9x-18)$

$\boxed{P(x)=-5x^3-40x^2-45x+90}$

3 0

2 years ago

PLEASE HELP ME!!! The formula F =95C + 32 expresses Fahrenheit temperature in terms of Celsius temperature. Find the Celsius tem

Jet001 [13]

Answer:

4C

Step-by-step explanation:

41= x+32

x= 41-32

x = 4C

6 0

2 years ago

Use three fours to make 11.

mr Goodwill [35]

4 + 4 + 4 - 1 = 11? Was it supposed to be an equation? I am confused.

7 0

2 years ago