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olga55 [171]
3 years ago
7

Find the distance between points P(7, 2) and Q(1, 8) in simplest radical form.

Mathematics
2 answers:
DochEvi [55]3 years ago
6 0

Answer:

d= √  72

Step-by-step explanation:

d=√  (1−7)2+(8−2)2

d=√  (−6)2+(6)2

d=√  36+36

d=√  72

d=8.485281

Ivahew [28]3 years ago
4 0

Answer:

Distance is 8.49 units

Step-by-step explanation:

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Given:
Cost of printing a catalog: flat rate of $52 and $0.20 per copy.

C = 52 + 0.20x

C is the total cost of printing x number of copies.

x = 500
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x = 1000
C = 52 + 0.20(1000) = 52 + 200 = 252

x = 1500
C = 52 + 0.20(1500) = 52 + 300 = 352

x = 2000
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x = 2500
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4 0
3 years ago
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Six customers enter a three-floor restaurant. Each customer decides on which floor to have dinner. Assume that the decisions of
Firdavs [7]
<h2>Answer:</h2>

The probability that exactly one customer dines on the first floor is:

                     0.26337  

<h2>Step-by-step explanation:</h2>

We need to use the binomial theorem to find the probability.

The probability of k success in n experiments is given by:

       P(X=k)=n_C_k\cdot p^k\cdot (1-p)^{n-k}

where p is the probability of success.

Here p=1/3

( It represents the probability of choosing first floor)

k=1 ( since only one customer has to chose first floor)

n=6 since there are a total of 6 customers.

This means that:

P(X=1)=6_C_1\times (\dfrac{1}{3})^1\times (1-\dfrac{1}{3})^{6-1}\\\\\\P(X=1)=6\times (\dfrac{1}{3})\times (\dfrac{2}{3})^5\\\\\\P(X=1)=0.26337

6 0
4 years ago
A bank offers auto loans to qualified customers. The amount of the loans are normally distributed and have a known population st
vlabodo [156]

Answer: 1.467

Step-by-step explanation:

Formula of Margin of Error for (n<30):-

E=t_{\alpha/2}\dfrac{\sigma}{\sqrt{n}}

Given : Sample size : n= 22

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Significance level : \alpha=1-0.90=0.10

By using the t-distribution table ,

Critical value : t_{n-1, \alpha/2}=t_{21,0.05}= 1.720743

Standard deviation: \sigma=4

Then, we have

E=(1.720743)\dfrac{4}{\sqrt{22}}=1.46745456106\approx1.467

Hence, the margin of error for the confidence interval for the population mean with a 90% confidence level =1.467

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3 years ago
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3 years ago
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