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kupik [55]
4 years ago
15

In a group of 1,200 people, 468 have brown eyes, 252 have blue eyes, 132 have green eyes, and 348 have black eyes. What is the p

robability that a person chosen at random from this group has blue eyes?
A.P(blue) = 11%
B.P(blue) = 29%
C.P(blue) = 21%
D.P(blue) = 39%
Mathematics
1 answer:
Blizzard [7]4 years ago
7 0

<u>Answer:</u>

The correct answer option is C. P(blue) = 21%.

<u>Step-by-step explanation:</u>

We know that,

the total number of people in a group = 1200

the number of people with brown eyes = 468

the number of people with blue eyes = 252

the number of people with green eyes = 132

the number of people with black eyes = 348

To find the probability of a person with blue eyes to be chosen, we will divide the number of people with blue eyes by the total number of people in the group and multiply it by 100.

P (blue) = \frac{252}{1200} × 100 = 21%

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