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kupik [55]
4 years ago
15

In a group of 1,200 people, 468 have brown eyes, 252 have blue eyes, 132 have green eyes, and 348 have black eyes. What is the p

robability that a person chosen at random from this group has blue eyes?
A.P(blue) = 11%
B.P(blue) = 29%
C.P(blue) = 21%
D.P(blue) = 39%
Mathematics
1 answer:
Blizzard [7]4 years ago
7 0

<u>Answer:</u>

The correct answer option is C. P(blue) = 21%.

<u>Step-by-step explanation:</u>

We know that,

the total number of people in a group = 1200

the number of people with brown eyes = 468

the number of people with blue eyes = 252

the number of people with green eyes = 132

the number of people with black eyes = 348

To find the probability of a person with blue eyes to be chosen, we will divide the number of people with blue eyes by the total number of people in the group and multiply it by 100.

P (blue) = \frac{252}{1200} × 100 = 21%

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A number is called evil if it has 666 in it. How many 7 digit numbers are evil?
defon

Step-by-step explanation:

There are 5 different positions of 666:

666////

/666///

//666//

///666/

////666

The forward dashes represent any number from 0 to 9.

Case 1: "666////"

Number of ways = 10⁴ = 10,000.

Case 2: The other positions.

Since the 1st forward dash cannot be 0 (leading digit),

Number of ways for each position = 9 * 10³ = 9,000

Number of ways for all 4 positions = 9,000 * 4 = 36,000.

Total evil numbers = 10,000 + 36,000 = 46,000.

5 0
3 years ago
Write the expression in standard form.<br><br> 6/(4-13i)
Paha777 [63]
6/(4 - 13i) = 6/(4 - 13i) * (4 + 13i)/(4 + 13i) = (24 + 78i)/(16 + 169) = 6/185 (4 + 13i)
7 0
3 years ago
Read 2 more answers
(1 point) All that is left in a packet of candy are 7 reds, 3 greens, and 3 blues.
Sauron [17]

Answer:

A 21 /169

B independent

Step-by-step explanation:

The total number of candies is 7+3+3 = 13

P( 1st red) = red/total = 7/13

Since the candy is put back there are still 13 candies in the dish

P(2nd green) = green/total = 3/13

P( red, then green) = P( 1st red) * P(2nd green)

                                = 7/13* 3/13 = 21/169

The events are independent since the candies are put back

4 0
3 years ago
Consider a sample with data values of 27, 24, 21, 16, 30, 33, 28, and 24. Compute the 20th, 25th, 65th, and 75th percentiles. 20
densk [106]

Answer:

P_{20} = 20 --- 20th percentile

P_{25} = 21.75  --- 25th percentile

P_{65} = 27.85   --- 65th percentile

P_{75} = 29.5   --- 75th percentile

Step-by-step explanation:

Given

27, 24, 21, 16, 30, 33, 28, and 24.

N = 8

First, arrange the data in ascending order:

Arranged data: 16, 21, 24, 24, 27, 28, 30, 33

Solving (a): The 20th percentile

This is calculated as:

P_{20} = 20 * \frac{N +1}{100}

P_{20} = 20 * \frac{8 +1}{100}

P_{20} = 20 * \frac{9}{100}

P_{20} = \frac{20 * 9}{100}

P_{20} = \frac{180}{100}

P_{20} = 1.8th\ item

This is then calculated as:

P_{20} = 1st\ Item +0.8(2nd\ Item - 1st\ Item)

P_{20} = 16 + 0.8*(21 - 16)

P_{20} = 16 + 0.8*5

P_{20} = 16 + 4

P_{20} = 20

Solving (b): The 25th percentile

This is calculated as:

P_{25} = 25 * \frac{N +1}{100}

P_{25} = 25 * \frac{8 +1}{100}

P_{25} = 25 * \frac{9}{100}

P_{25} = \frac{25 * 9}{100}

P_{25} = \frac{225}{100}

P_{25} = 2.25\ th

This is then calculated as:

P_{25} = 2nd\ item + 0.25(3rd\ item-2nd\ item)

P_{25} = 21 + 0.25(24-21)

P_{25} = 21 + 0.25(3)

P_{25} = 21 + 0.75

P_{25} = 21.75

Solving (c): The 65th percentile

This is calculated as:

P_{65} = 65 * \frac{N +1}{100}

P_{65} = 65 * \frac{8 +1}{100}

P_{65} = 65 * \frac{9}{100}

P_{65} = \frac{65 * 9}{100}

P_{65} = \frac{585}{100}

P_{65} = 5.85\th

This is then calculated as:

P_{65} = 5th + 0.85(6th - 5th)

P_{65} = 27 + 0.85(28 - 27)

P_{65} = 27 + 0.85(1)

P_{65} = 27 + 0.85

P_{65} = 27.85

Solving (d): The 75th percentile

This is calculated as:

P_{75} = 75 * \frac{N +1}{100}

P_{75} = 75 * \frac{8 +1}{100}

P_{75} = 75 * \frac{9}{100}

P_{75} = \frac{75 * 9}{100}

P_{75} = \frac{675}{100}

P_{75} = 6.75th

This is then calculated as:

P_{75} = 6th + 0.75(7th - 6th)

P_{75} = 28 + 0.75(30- 28)

P_{75} = 28 + 0.75(2)

P_{75} = 28 + 1.5

P_{75} = 29.5

7 0
3 years ago
If the probability that event A takes place is 1/5, what is the probability of event A not
steposvetlana [31]
The probability is 4/5
4 0
4 years ago
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