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lianna [129]
3 years ago
9

What sorts of routine, seemingly unimportant information would help you learn about or break into another company’s network?

Computers and Technology
1 answer:
tatuchka [14]3 years ago
4 0

Answer and Explanation:

  • Reboot your Computer from which you need to break into.
  • With your remote Ethernet card embedded and the unprotected passageway will mate up in a flash. You likewise need to change the Service Set Identifier (SSID) on your Ethernet card to coordinate SSID on the system's passage. You can decide to physically constrain your DHCP settings to reestablish, however on the off chance that that gives you any trouble.we need to re-boot it.
  • The Third Man ran a sniffer program that caught the majority of the LAN traffic within this organization. It was transmitted through the remote passageway straight into the Third Man's PC. Passwords. Agreements. Email.
You might be interested in
How do most business applications and websites process credit card transactions?
klasskru [66]

Answer:

The answer to this question is given below in the explanation section.

Explanation:

Most business applications and websites use and process the credit card for their transaction.

For example, e-commerce website such as ali baba, am a zon, accepting credit card transaction when the customer gets to purchase any product from their stores. Their transactions are processed by in house credit card apps/service. But these apps/services owned by a third party. They just give you API services and related code to integrate the credit card services.  

By using their in-house credit card apps/services, they know that user has transferred the money into their account for the purchased product, upon receiving payment confirmation, they then prepare and dispatch the order.

So, the correct answer to this question is:

To process the credit card transactions, they license third-party credit card apps/services backed by the internet merchant who is responsible for handling and managing the money of the business account.    

6 0
3 years ago
What is the definition of "potential energy"?
muminat
Well potential energy is energy that is in a object while its not moving so i would go your third option 
4 0
3 years ago
Read 2 more answers
Define a member function PrintAll() for class PetData that prints output as follows. Hint: Make use of the base class' PrintAll(
PilotLPTM [1.2K]

Answer:

Following are the program in the C++ Programming Language.

//set header file

#include <iostream>

//set header file for string

#include <string>

//set namespace

using namespace std;

//define class

class AnimalData

{

//set access modifier

public:

//define function

void SetName(string givenName)

{

//initialize the value of function's argument

fullName = givenName;

};

//define function

void SetAge(int numYears)

{

//initialize the value of function's argument

ageYears = numYears;

};  

//here is the solution

//define function

void PrintAll()

{

//print output with message

cout << "Name: " << fullName<<endl;

//print output with message

cout << "Age: " << ageYears<<endl;

};

//set access modifier

private:

//set integer data type variable

int ageYears;

//set string data type variable

string fullName;

};

//define class and inherit the parent class

class PetData: public AnimalData

{

//set access modifier

public:

//define function

void SetID(int petID)

{

idNum = petID;

};

//override the function for print id

void PrintAll()

{

AnimalData::PrintAll();

cout << "ID: " <<idNum ;

};

//set access modifier

private:

//set integer type variables

int idNum,fullName,ageYears;

};

//define main method

int main()

{

//create object of the child class

PetData userPet;

//call function through object

userPet.SetName("Fluffy");

//call function through object

userPet.SetAge (5);

//call function through object

userPet.SetID (4444);

//call function through object

userPet.PrintAll();

cout << endl;

return 0;

}

<u>Output</u>:

Name: Fluffy

Age: 5

ID: 4444

Explanation:

<u>Following are the description of the program</u>:

  • Set required header file and namespace.
  • Define class 'AnimalData' and inside the class, set integer data type variable 'ageYears', string data type variable 'fullName'.
  1. Then, define function 'SetName()' with string data type argument 'givenName' and initialize the value of argument in the string variable.
  2. Then, define function 'SetAge()' with integer data type argument 'numYears' and initialize the value of the argument in the integer variable.
  3. Define function 'PrintAll()' to print the value of the following variables with message.
  • Define class 'PetData' and inherit the parent class in it, then set integer data type variable 'idNum'.
  1. Then, define function 'SetID()' with integer data type argument 'petID' and initialize the value of the argument in the integer variable.
  2. Override the function 'PrintAll()' to print the value of the following variable with message.

Finally, define main method and create the object of the child class, then call the following functions through the class object.

8 0
2 years ago
12. Write C statement(s) that accomplish the following. a. Declare int variables x and y. Initialize x to 25 and y to 18. b. Dec
saul85 [17]

Answer:

a.

int x = 25;

int y = 18;

b.

int temp = 10;

char ch ='a';

c.

x += 5;

d.

double payRate = 12.5;

e.

int tempNum = firstNum;

f.

int tempp = x;

x = y;

y = tempp;

g.

printf("Value of x = %f\n",x);

printf("Value of y = %f\n",y);

printf("Arithmetic = %f\n",(x + 12/y -18));

h.

char grade = 'A';

i.

int a,b,c,d;

a = 5; b = 2; c = 3; d = 6;

j.

int x = round(z);

Explanation:

The answers are straight forward.

However, I'll give a general hint in answering questions like this.

In C, variable declaration is done by:

data-type variable-name;

To declare and initialise the variable, you do;

data-type variable-name = value;

So, for questions that requires that we declare and initialise a variable, we make use of the above syntax..

Take (a) for instance:

int x = 25;

int y = 18;

Same syntax can be applied to (b), (d), (e), (h) & (I)

For question (c);

This can be done in two ways;

x = x + 5;

Or

x+=5;

Both will give the same result.

For question (f):

We start by initialise a temporary variable that stores x.

Then we store the value of x in y.

Then we store the content of the temporary variable to y.

This swaps the values of x and y

For question (g):

When printing a double variable in C, we make use of '\f' as a string format

For question (j):

The round function is used to round up a double variable to integer.

3 0
3 years ago
Write a program that reads a person's first and last names separated by a space, assuming the first and last names are both sing
Dmitriy789 [7]

<em>Complete Question:</em>

<em>Write a program that reads a person's first and last names, separated by a space. Then the program outputs last name, comma, first name. End with newline.  </em>

<em>Example output if the input is: Maya Jones </em>

<em>Jones, Maya</em>

<em></em>

<em>In C++</em>

<em></em>

Answer:

The program written in C++ is as follows

<em>#include<iostream></em>

<em>using namespace std;</em>

<em>int main(){</em>

<em>string lname, fname;</em>

<em>cout<<"First name: ";</em>

<em>cin>>fname;</em>

<em>cout<<"Last name: ";</em>

<em>cin>>lname;</em>

<em>cout<<lname<<", "<<fname;</em>

<em>return 0;</em>

<em>}</em>

<em />

Explanation:

This line declares lname, fname as string to get the user's last name and first name, respectively

<em>string lname, fname;</em>

This line prompts the user for first name

<em>cout<<"First name: ";</em>

This line gets the user first name

<em>cin>>fname;</em>

This line prompts the user for last name

<em>cout<<"Last name: ";</em>

This line gets the user last name

<em>cin>>lname;</em>

This line prints the desired output

<em>cout<<lname<<", "<<fname;</em>

7 0
3 years ago
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