Question

Solve the equations. a. 4a^2 = 16 b. 5????^2 − 25 = 0 c. 8 − c^2 = 5

Answer 1

Answer:

$a=\pm 2$, $x=\pm \sqrt{5}$ and $c=\pm \sqrt{3}$.

Step-by-step explanation:

Consider the given equations are

a. $4a^2=16$

b. $5x^2-25=0$

c. $8-c^2=5$

(a)

$4a^2=16$

Divide both sides by 4.

$a^2=4$

Taking square root on both sides.

$a=\pm \sqrt{4}$

$a=\pm 2$

(b)

$5x^2-25=0$

Add 25 on both sides.

$5x^2=25$

Divide both sides by 5.

$x^2=5$

Taking square root on both sides.

$x=\pm \sqrt{5}$

(c)

$8-c^2=5$

Subtract 8 from both sides.

$-c^2=-3$

Multiply both sides by -1.

$c^2=3$

Taking square root on both sides.

$c=\pm \sqrt{3}$