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3 years ago

Kevinhas$100inasavingsaccountthatearns10%interestperyear.Theinterestisnotcompounded.Howmuchinterestwillheearnin1year?

Mathematics

2 answers:

igor_vitrenko [27]3 years ago

8 0

I don't understand what the question is.. there are no spaces..

kakasveta [241]3 years ago

3 0

I don’t understand what the question is maybe space it out

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Solve equation:<br><img src="https://tex.z-dn.net/?f=y%20%2B%20%20%5Cfrac%7B7%7D%7B8%7D%20%20%3D%20%20%5Cfrac%7B3%7D%7B8%7D%20"

Gala2k [10]

Answer: y = -1/2

Step-by-step explanation:

Subtract both sides by 7/8

y = 3/8 - 7/8

Then combine like terms

y = -4/8

Then simplify

y = -1/2

4 0

3 years ago

5 Consider this system of equations:<br> 5x + y = -2<br> 2x - 2y=4

Ilia_Sergeevich [38]

Answer:

x = 0

y = -2

Step-by-step explanation:

The given system of equation are:

5x + y = -2

2x - 2y = 4

The problem here is to find x and y from the expression

5x + y = -2 ----- i

2x - 2y = 4 ---- ii

So;

i x 2 : 10x + 2y = -4 ---- iii

ii x 5 : 10x - 10y = 20 ----- iv

iii - iv; 12y = -24

y = -2

Now find x;

5x + y = -2

5x - 2 = -2

x = 0

7 0

3 years ago

Which function represents exponential growth

marta [7]

The exponential function with a base greater than 1 is

14(1.95)^x

4 0

4 years ago

Read 2 more answers

Does Biased mean random or not random?

mote1985 [20]

Biased most likely means not random in this context. The actual definition is "unfairly prejudiced for or against someone or something"

7 0

4 years ago

Read 2 more answers

In the 1990s the demand for personal computers in the home went up with household income. For a given community in the 1990s, th

WITCHER [35]

Answer:

a) 0.5198 computers per household

b) 0.01153 computers

Step-by-step explanation:

Given:

number of computers in a home,

q = 0.3458 ln x - 3.045 ; 10,000 ≤ x ≤ 125,000

here x is mean household income

mean income = $30,000

increasing rate, $\frac{dx}{dt}$ = $1,000

Now,

a) computers per household are

since,

mean income of $30,000 lies in the range of 10,000 ≤ x ≤ 125,000

thus,

q = 0.3458 ln(30,000) - 3.045

q = 0.5198 computers per household

b) Rate of increase in computers i.e $\frac{dq}{dt}$

$\frac{dq}{dt}$ = $\frac{d(0.3458 ln x - 3.045)}{dt}$

$\frac{dq}{dt}=0.3458\times(\frac{1}{x})\frac{dx}{dt} - 0$

on substituting the values, we get

$\frac{dq}{dt}=0.3458\times(\frac{1}{30,000})\times1,000$

= 0.01153 computers

6 0

3 years ago