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3 years ago

Please help!!!!!!20 points

Mathematics

1 answer:

Anika [276]3 years ago

7 0

Ah You Must Divide Im Getting You An Answer But Just Know You Must Divide

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Estimate the answer to

AlladinOne [14]

Answer:

~ 80.75 x 10^7

Step-by-step explanation:

9 x 8 + 9 * .5 + .5 * 8 + .5 * . 5 = ~ 80.75 x 10 ^7

4 0

1 year ago

QUICKEST GETS BRAINLIEST AND 14 POINTS!!! PLEASE HURRY!!

andrezito [222]

Machine J's equation would be 30x=y. To find out how many more candies Machine J packets, You would plug in 11 as x and you would get 330.
For Machine K, you would just plug in 11 as x. Your answer is 286.
Now you would subtract. 330-286=44.

7 0

3 years ago

Eric's class consists of 12 males and 16 females. If 3 students are selected at random, find the probability that they

Reptile [31]

Answer:

The probability that all are male of choosing '3' students

P(E) = 0.067 = 6.71%

Step-by-step explanation:

Let 'M' be the event of selecting males n(M) = 12

Number of ways of choosing 3 students From all males and females

$n(M) = 28C_{3} = \frac{28!}{(28-3)!3!} =\frac{28 X 27 X 26}{3 X 2 X 1 } = 3,276$

Number of ways of choosing 3 students From all males

$n(M) = 12C_{3} = \frac{12!}{(12-3)!3!} =\frac{12 X 11 X 10}{3 X 2 X 1 } =220$

The probability that all are male of choosing '3' students

$P(E) = \frac{n(M)}{n(S)} = \frac{12 C_{3} }{28 C_{3} }$

$P(E) = \frac{12 C_{3} }{28 C_{3} } = \frac{220}{3276}$

P(E) = 0.067 = 6.71%

Final answer:-

The probability that all are male of choosing '3' students

P(E) = 0.067 = 6.71%

3 0

3 years ago

Write the order of operations down using your own words

dybincka [34]

The order of operations is:

Parentheses, Exponent, Division, Multiplication, Addition, Subtraction.

Or PEMDAS.

hope it helps!

6 0

2 years ago

Which of the following is an integer? 0.5 1 3/2

Vinil7 [7]

Yeah the answer is one

3 0

2 years ago

Read 2 more answers