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bearhunter [10]
3 years ago
9

Who among the following was mentioned as asking what it means to live a good life?

Business
1 answer:
VikaD [51]3 years ago
4 0

Answer:

Who among the following was mentioned as asking what it means to live a good life?

Aristotle

Explanation:

Aristotle was a philosopher and a writer in ancient Greece. He was a founder of different philosophical schools. He was taught by Plato, and together they have been collectively referred to as 'The Father of Western philosophy.' Many writings have been attributed to him. One such writing was when he asked."what it means to live a good life?"He used what he termed as Nicomachean ethics to describe what it meant to live a good life.

In nicomachean ethics, Aristotle aimed to determine the highest good for a human beings. He stated that what most people thought of the highest good for human beings was actually insignificant. Most people considered material wealth and satisfaction of bodily pleasure as the highest good for human beings, a concept that Aristotle disagreed with. He alluded that the highest good for human beings has to be consistent maximization of our faculties as human beings. One such endeavor was the acquisition of intellectual virtues through contemplation and learning.

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aaron is earning 5% interest on his savings account. he starts with $5,000.00. how much money will he have in 6 months?
Anvisha [2.4K]

Answer:

I think the answer is $1,500.

Explanation:

I hope this helps. If the answer is wrong then sorry and you don't have to give me the points. In here I think I did the calculation wrong.

7 0
2 years ago
Each machine must be run by one of 19 cross-trained workers who are each available 35 hours per week. The plant has 10 type 1 ma
Mrac [35]

Answer:

The Linear programming model is given as below

Profit Function: P=90X+120Y+150Z

Constraints:

2X+2Y+Z\leq 400

3X+4Y+6Z\leq 240

4X+6Y+5Z\leq 320

\dfrac{2X+2Y+Z}{40}\leq 10

\dfrac{3X+4Y+6Z}{40}\leq 6

\dfrac{4X+6Y+5Z}{40}\leq 8

\dfrac{2X+2Y+Z}{35}+\dfrac{3X+4Y+6Z}{35}+\dfrac{4X+6Y+5Z}{35}\leq 19

Explanation:

As the question is not complete, the complete question is found online and is attached herewith.

Let the number of product 1 to be produced is X, that of product 2 is Y and product 3 is Z

so  the maximizing function is the profit function which is given as

P=90X+120Y+150Z

Now as the number of hours in a week are 40 and there are a total of 10 type 1 machines so the total number of machine 1 hours are 40*10=400 hours

As from the given table product 1 uses 2 machine hours of machine 1, product 2 uses 2 machine hours of machine 1 and product 3 uses 1 hour of machine 1 so

2X+2Y+Z\leq 400

Now as the number of hours in a week are 40 and there are a total of 6 type 2 machines so the total number of machine 2 hours are 40*6=240 hours

As from the given table product 1 uses 3 machine hours of machine 2, product 2 uses 4 machine hours of machine 2 and product 3 uses 6 hour of machine 2 so

3X+4Y+6Z\leq 240

Now as the number of hours in a week are 40 and there are a total of 8 type 3 machines so the total number of machine 3 hours are 40*8=320 hours

As from the given table product 1 uses 4 machine hours of machine 3, product 2 uses 6 machine hours of machine 3 and product 3 uses 5 hour of machine 3 so

4X+6Y+5Z\leq 320

Now as the machine 1 is used as 2X+2Y+Z in a week and the week is of 40 hours so the number of machines to be used are given as

\dfrac{2X+2Y+Z}{40}\leq 10

Now as the machine 2 is used as 3X+4Y+6Z in a week and the week is of 40 hours so the number of machines to be used are given as

\dfrac{3X+4Y+6Z}{40}\leq 6

Now as the machine 3 is used as 4X+6Y+5Z in a week and the week is of 40 hours so the number of machines to be used are given as

\dfrac{4X+6Y+5Z}{40}\leq 8

Now the workers are available for 35 hours so the worker available at the machine 1 is given as

\dfrac{2X+2Y+Z}{35}

That of machine 2 is given as

\dfrac{3X+4Y+6Z}{35}

That of machine 3 is given as

\dfrac{4X+6Y+5Z}{35}

As the total number of workers is 19 so the constraint is given as

\dfrac{2X+2Y+Z}{35}+\dfrac{3X+4Y+6Z}{35}+\dfrac{4X+6Y+5Z}{35}\leq 19

So the Linear programming model is given as below

Profit Function: P=90X+120Y+150Z

Constraints:

2X+2Y+Z\leq 400

3X+4Y+6Z\leq 240

4X+6Y+5Z\leq 320

\dfrac{2X+2Y+Z}{40}\leq 10

\dfrac{3X+4Y+6Z}{40}\leq 6

\dfrac{4X+6Y+5Z}{40}\leq 8

\dfrac{2X+2Y+Z}{35}+\dfrac{3X+4Y+6Z}{35}+\dfrac{4X+6Y+5Z}{35}\leq 19

4 0
3 years ago
While working at his factory job, joe slipped on the wet floor. he went to the doctor where they told him he broke his ankle. wh
Svetlanka [38]

Worker's Compensation, because the injury occurred by an employee in the course of performing their job.

4 0
3 years ago
A university is trying to determine what price to charge for tickets to football games. At a price of ​$24 per​ ticket, attendan
m_a_m_a [10]

Answer:<u><em>  Price per ticket should be charged in order to maximize​ revenue is $15.</em></u>

<u><em>70000 people will attend at this price.</em></u>

<u><em></em></u>

Explanation:

Let 'x' represent the decrease .

Using the given information,

Price per ticket = 24 - 3x

Average no. of people that watch the game = 40000 + 10000x

Additional money spent by every person = 6(40000 + 10000x)

Revenue [R(x)] = Price per ticket \times Average no. of people that watch the game + Additional money spent

Revenue [R(x)] = (24 - 3x)\times(40000 + 10000x) + 6(40000 + 10000x)

On solving the above equation we get ,

Revenue [R(x)] = -30000x^{2} + 180000x + 1200000

In order to find the critical point we'll differentiate the following with respect to x;

R'(x) = -60000x + 180000

∵ R'(x) = 0  

x = 3

<u><em>Thus, the price per ticket that should be charged in order to maximize​ revenue is (24 - 3\times3 = 24 - 9 = $15)</em></u>

<u><em>People that will attend at this price = (40000 + 10000\times3) = 70000</em></u>

7 0
3 years ago
Presented below are the ending balances of accounts for the Kansas Instruments Corporation at December 31, 2021.
dedylja [7]

Solution :

Current Assets

Cash                                                                     $ 20,000

Accounts receivable                                           $ 1,30,000

Less: Allowance for uncollectible accounts     - $ 13,000

Note receivable                                                    $ 100,000

Interest receivable                                                $ 3,000

Marketable securities                                           $ 32,000

Raw materials                                                       $ 24,000

Work in process                                                   $ 42,000

Finished goods                                                    $ 89,000

Prepaid Rent(Half of $ 60,000)                    <u>      $ 30,000      </u>

Total current assets                                             $ 4,57,000

Current Liabilities

Deferred revenue ($36,000/2)                           $ 18,000

Accounts payable                                                $ 1,80,000

Interest payable                                              <u>     $ 5000           </u>

Total current liabilities                                          $ 2,03,000

Working capital (4,57,000 - 2,03,000)           $ 2,54,000

8 0
3 years ago
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