All categories

3 years ago

What are the solutions for the equation 2cos0+1=0 ?

Mathematics

1 answer:

Oksanka [162]3 years ago

4 0

Answer:

2cos0=-1

cos0=-1/2

proved

You might be interested in

If B is the midpoint of AC, AC= CD, AB=3x+4, AC= 11x-17, and CE= 49 , find DE

melisa1 [442]

Answer:

Ehhh

Step-by-step explanation:

4 0

2 years ago

Find the integration of (1-cos2x)/(1+cos2x)

slega [8]

Given:

The expression is:

$\dfrac{1-\cos 2x}{1+\cos 2x}$

To find:

The integration of the given expression.

Solution:

We need to find the integration of $\dfrac{1-\cos 2x}{1+\cos 2x}$ .

Let us consider,

$I=\int \dfrac{1-\cos 2x}{1+\cos 2x}dx$

$I=\int \dfrac{2\sin^2x}{2\cos^2x}dx$ $[\because 1+\cos 2x=2\cos^2x,1-\cos 2x=2\sin^2x]$

$I=\int \dfrac{\sin^2x}{\cos^2x}dx$

$I=\int \tan^2xdx$ $\left[\because \tan \theta =\dfrac{\sin \theta}{\cos \theta}\right]$

It can be written as:

$I=\int (\sec^2x-1)dx$ $[\because 1+\tan^2 \theta =\sec^2 \theta]$

$I=\int \sec^2xdx-\int 1dx$

$I=\tan x-x+C$

Therefore, the integration of $\dfrac{1-\cos 2x}{1+\cos 2x}$ is $I=\tan x-x+C$ .

8 0

2 years ago

13. Solve for s. 2(s + 7) = 12

Tatiana [17]

2s+14=12
2s=-14+12
2s=-2
s=-2÷2
s=-1

4 0

3 years ago

Read 2 more answers

if you’re good with set theory in math 30 please help with questions 31 and 32!! real answers only !!

GREYUIT [131]

Answer: 31) d 32) c

<u>Step-by-step explanation:</u>

31)

A = {1, 3, 5, 15}

B = {2, 3, 5, 7}

A ∪ B = {1, 2, 3, 5, 7, 15}

C = {2, 4, 6, 8}

(A ∪ B) ∩ C = {1, 2, 3, 5, 7, 15} ∩ {2, 4, 6, 8} = {2}

<em>2 is the only number in both sets</em>

32)

The pattern is: reflection, add symbol, ..., reflection, add symbol.

The last image shown is: add symbol

So the next image will be: reflection (flipped to the left)

7 0

2 years ago

Question 4 This question has two parts. First, answer Part A. Then, answer Part B. Part A Fill in the blank question. COLLEGE LI

Annette [7]

The equation that models the number of students who live in apartments will be 6n + 15

<h3>How to illustrate the equation?</h3>

Total number of students T = 17n + 23

Students who live in dorm rooms on campus D = 11n + 8.

Therefore, the students who live in apartments will be:

= 17n + 23 - (11n + 8)

= 6n + 15

In order to predict the number of students who will live on campus in 2020, we will need the students that do not share dorm rooms.

Learn more about equations on:

brainly.com/question/2972832

#SPJ1

7 0

1 year ago