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3 years ago

Calculate the average rate of change of the quadratic function y = -x2 + 4x +2

Mathematics

1 answer:

algol133 years ago

6 0

Answer:

Step-by-step explanation:

The average rate of change of f(x) in the closed interval [ a, b ] is

$\frac{f(b)-f(a)}{b-a}$

Here [ a, b ] = [ 0, 2 ], thus

f(b) = f(2) = -(2)² + 4)(2) + 2 = - 4 + 8 + 2 = 6

f(a) = f(0) = 2

average rate of change = $\frac{6-2}{2-0}$ = $\frac{4}{2}$ = 2

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A company's stock begins the week with a price of $43.85 per share. THe price changes by +$2.70 each day for the first two days,

mixas84 [53]

Given:

Initial price of the stock=$43.85

Change for the first two days=+$2.70

Change for next two days=-$1.10

Last day=-$4.45

The objective is to find the price at the last day.

Let's take the price at final day as x.

$\begin{gathered} x=43.85+2.70+2.70-1.10-1.10-4.45 \\ x=42.6 \end{gathered}$

Hence, the price of the stock at the last day is $42.6

5 0

1 year ago

Question 3 (1 point)

Virty [35]

Answer:

The answer to your question is (4, 6)

Step-by-step explanation:

Data

E ( 9 , 7 )

F ( - 1, 5)

Formula

$Xm = \frac{x1 + x2}{2}$

$Ym = \frac{y1 + y2}{2}$

Substitution and simplification

$Xm = \frac{9 -1}{2}$

$Xm = \frac{8}{2}$

Xm = 4

$Ym = \frac{7 + 5}{2}$

$Ym = \frac{12}{2}$

Ym = 6

Result

(4 , 6)

7 0

3 years ago

How do you check your solutions

Fantom [35]

Reverse your steps to see if u get what the questions originally asked.

8 0

3 years ago

A rectangular billboard is 9.35 meters wide and 6.82 meters tall what is the perimeter of the billboard in meters?

kati45 [8]

-The perimeter is the length of the line if the whole rectangle was straightened out.
-a rectangle has 2 sets of 2 even sides. The top and bottom width would be equal and the two heights would be equal

Armed with these two facts we know the perimeter would be Side A + Side B + Side C + Side D
9.35 + 9.35 + 6.82 + 6.82 = ?

The actual formula for a rectangle or even a square is
2(length + width)

6 1

3 years ago

Read 3 more answers

What is the greatest common factor of the terms in the polynomial 4x^4-32x^3-60x^2?

jonny [76]

Answer:

$\mathrm{Factor}\:4x^4-32x^3-60x^2:\quad 4x^2\left(x^2-8x-15\right)\\$

$\mathrm{Apply\:exponent\:rule}:\quad \:a^{b+c}=a^ba^c\\x^3=xx^2\\x^4=x^2x^2\\=4x^2x^2-32xx^2-60x^2\\\mathrm{Rewrite\:}60\mathrm{\:as\:}4\cdot \:15\\\mathrm{Rewrite\:}32\mathrm{\:as\:}4\cdot \:8\\=4x^2x^2-4\cdot \:8xx^2-4\cdot \:15x^2\\\mathrm{Factor\:out\:common\:term\:}4x^2\\=4x^2\left(x^2-8x-15\right)$

Hope this helps and have a great day!!!

$Sofia$

4 0

3 years ago