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anyanavicka [17]
3 years ago
8

12 divided by 768,907 times that by 3 add 6 yaaake away 7

Mathematics
1 answer:
lisabon 2012 [21]3 years ago
7 0

Answer:

6.00004682 lolll

Step-by-step explanation:

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Please help! view the picture :) <br> due soon
arlik [135]

The answer is 30~~~~~~~~

3 0
2 years ago
B. A number cube is rolled once. What are the odds of rolling a 6?​
GREYUIT [131]

Answer:

If by "Number cube" you mean a die, then the odds of rolling a six are

    _

0.167 or \frac{1}{6}

8 0
3 years ago
Read 2 more answers
Find the area of the shaded region in the figure below. 5in. 8in.
Fiesta28 [93]

Hi there!

<u>Answer:</u>

The area of the shaded region is 28 in²


<u>Step-by-step explanation:</u>

You will have to do 3 different steps in order to find the area of the shaded region.

First, you will need to find the total area of the rectangle using the values you have and the area formula for a rectangle, which is : A = Length × Width

"A" is the area, which is what we are looking for

The "Length" is equal here to 8 inches

The "Width" is equal here to 5 inches


A = <u>8 × 5</u>

A = 40 in²


Now that you have the area of the rectanlge, your second step is to find the area of the triangle using the values you have and the area formula for a triangle, which is : A = (Base × Height) ÷ 2

"A" is the area, which is what we are looking for

The "Base" is equal here to 8 inches

The "Height" is equal here to 3 inches


A = <u>(8 × 3)</u> ÷ 2

A = <u>24 ÷ 2</u>

A = 12 in²


Now that you have both the area of the rectangle and the area of the triangle, all you have to do for your third and final step is subtract the area of the triangle from the area of the rectangle so that you are left with the area of the shaded region :

Area shaded region = <u>40 in² - 12 in²</u>

Area shaded region = 28 in²


There you go! I really hope this helped, if there's anything just let me know! :)

6 0
3 years ago
Zack drew a scale drawing of a house and its lot. The backyard is 15 inches wide in the drawing. The actual yard is 24 feet wide
lana66690 [7]

Answer:

  • 5 ÷ 96

Step-by-step explanation:

<u>The scale is </u>

  • 15 in ÷ 24 feet =
  • 15 in ÷ 24*12 in =
  • 15 in ÷ 288 in =
  • 5 in ÷ 96 in =
  • 5 ÷ 96
6 0
3 years ago
A simple random sample from a population with a normal distribution of 99 body temperatures has xbar = 99.10°F and s = 0.64°F. C
motikmotik

The general formula for the margin of error is e = (zs)/√n, when the sample size is 30 or more (otherwise, we'd need to to a t-interval).

Since we're needing a 99% confidence interval, we need to know what the positive z-score associated with this two-tailed area under the normal curve is.  This can be a little tricky if you're using a standard normal table.  What you want is a two-tailed interval that has an area of .99.  What this means is that the remaining 0.01 is divided into 0.005 on each end.  This then means that, to the right of the mean (which is 0), the area is 0.005 less than the total right-half area of 0.5, or 0.495.  The total cumulative area, then, includes this plus the left half of .5, or 0.5 + 0.495 = .0995.

Then, if all we have to go on is a cumulative standard normal table, then we need to find the area closest to 0.995 and find the corresponding z-score.  This z-score is 2.58.

Now that we have the z-score, we can now plug in all the values into the formula.  

e = (2.58 · 0.66)/√102 = 0.1686.

So the 99% confidence interval will be that far above and below the mean (which is 98.8).  So the lower limit is 98.8 - 0.1686 = 98.631, and the upper limit is 98.8 + 0.1686 = 98.967.

The TI-84 method:

This is much easier, if you're allowed to use this technology.  You begin with the STAT button, and then move over to the TESTS menu.  Then select ZInterval.  We have summary stats rather than data in this problem, so we select Stats as the input.  For the standard deviation, we put 0.66, for x-bar 98.8, for n 102, and for C-level 0.99.  Then select Calculate, and it will provide the interval at the top of the screen (98.632, 98.968).  Note that the lower limit is slightly different by this method.  This is because, when doing it by hand, we had to approximate the z-score.  This created a rounding error, albeit  a small one.

4 0
2 years ago
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