4 years ago

Please Answer ASAP!!!

Mathematics

2 answers:

kirill115 [55]4 years ago

8 0

Answer: g(1) is 1.

Step-by-step explanation:

If we are solving for g of 1 then the first equation can't be used to solve for g of 1 because it only works in x is equal to -2.

The same way the second function will not work because x has to equal to -1.

But in the last function which is written as a polynomial it will work for this situation because x is not equal to -2 or -1 so apart from those numbers every number will work the same way 1 will work.

So plot 1 into the function and solve for it .

g(1) = 1^3 - 1^2 + 1

g(1)= 1 - 1 + 1

g(1)= 1

amid [387]4 years ago

5 0

G(1) is 1. 1 is the answer to your question

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