If we are solving for g of 1 then the first equation can't be used to solve for g of 1 because it only works in x is equal to -2.
The same way the second function will not work because x has to equal to -1.
But in the last function which is written as a polynomial it will work for this situation because x is not equal to -2 or -1 so apart from those numbers every number will work the same way 1 will work.
