Given that the ratio of three trays is A : B : C = 2 : 3 : 4
Let us consider the common factor among the number of trays be "x".
If we need to make a total of 171 trays, then the equation of sum of trays would be :-
Type A + Type B + Type C = 171
2x + 3x + 4x = 171
9x = 171
x =
= 19
So we have following number of trays :-
Number of type A trays = 2x = 38 trays.
Number of type B trays = 3x = 57 trays.
Number of type C trays = 4x = 76 trays.
Now if each tray contains 20 cookies, then we would have following arrangements :-
Cookies in type A trays = 38×20 = 760 cookies.
Cookies in type B trays = 57×20 = 1140 cookies.
Cookies in type C trays = 76×20 = 1520 cookies.
Answer:
I just summited it, it was "Her mean grade would go up".
Step-by-step explanation:
Answer:
118 I guess
Step-by-step explanation:
a and B are both congruent so it's both 31 and you subtract 62 from 180
Answer:
38/100
Step-by-step explanation:
To combine the amounts, add the fractions with a common denominator.
3/10 kilogram flour is 30/100.
8/100 kilogram of sugar.
Both now have the same denominator. Add the numerators to find the total.
30/100 + 8/100 = 38/100
|-5x + 8| + 2 < 25 -> 5x +8 + 2 < 25 -> 5x + 10 < 25 ->(subtract 10) 5x < 15 ->(divide 5) x < 3
x < 3 = Final Answer