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SOVA2 [1]
4 years ago
8

Consider two​ investments, one earning simple interest and one earning compound interest. If both start with the same initial de

posit​ (and you make no other deposits or​ withdrawals) and earn the same annual interest​ rate, how will the balance in the simple interest account compare to that of the compound​ interest?
Mathematics
1 answer:
Len [333]4 years ago
6 0

Answer:

Ratio between balances will be:

(x*(1+i)*n)/(x*(1+i)^n)

Where;

x = deposit

%i = interest rate annual

n = years

Step-by-step explanation:

Lets say first deposit is x$ for both investment and annual interest rate for both investment are %i. Also, they stayed under i interest in n years:

Total balance for simple interest is:

Total balance=x*(1+i)*n

How ever total balance for compound interest is:

Total balance=x(1+i)^n

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Ket [755]
Since Marco makes 10$ an hour for every dog he walks, we need to see how much money he would make per minute.

To find out how much money he makes per minute, we divide 10.00 by 60.

10.00÷60= 0.16666

Since it's an extended decimal we round it, so he makes about $0.17 per minute.

Next, we multiply 0.17 by 12, so we know how much money he makes every twelve minutes. 

0.17×12=2.04

He makes around $2.04 every twelve minutes.

Since he's walking 5 dogs, we multiply 2.04 by five.

2.04×5=10.20

That means <em>he earns $10.20</em>.

I hope you have a wonderful day! :D
7 0
3 years ago
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kotegsom [21]
The area is given by
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 Rewriting we have:
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Answer:

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Step-by-step explanation:

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