First distribute in the 2 on the left side to get 6d+6=7+6d
Then, you would combine the variables to be on one side of the equation by doing -6d. However, this would cancel out the d by leaving you with 0d+6=7. That is the same thing as saying 6=7.
The answer to this equation is no solution because 6 is NOT equal to 7.
Answer:
x^2 + 10x + 24
Step-by-step explanation:
(x+6)(x+4)
x^2 + 4x + 6x + 24
x^2 + 10x + 24
Answer:
In 5:
UM and MS are equal since the diagonals US and VT have perpendicularly bisected each other.
So,15=6x-3
15+3=6x
18=6x
3=x
In 6:
ET=TC
8=x-4
8+4=x
12=x
ax^2 +bx+c=0
X^2 + 2x+8=0 so a=1, b=2, c=8
Discriminat= b^2 -4ac=2^2 -4•1•8=4-32=-28
So there are no real number solutions, yet there are complex numbers solutions.
Solutions=(-b+- sqrt (discriminant))/2•a
=(-2+-i sqrt ( 2•2•7))/2
Solutia 1= -1 + i sqrt7
Solutia 2= -1 - i sqrt 7
2log10(2vx2) is the answer
