All categories

2 years ago

-2(x+2) < 14 What is the answer

1 answer:

5 0

Answer:
x>-9

Explanation:

move constant to the right
x+2>-7

calculate
x>-2-7

x>-9

the reason you flip the sign is because you multiplied with a negative number. always flip sign if the number you are either multiplying or dividing by is a negative. if it is positive then keep the sign the way it is.

You might be interested in

Mr. Chase is having a party for his teachers. If the pizzeria cuts their pies into eight slices and each teacher is eating 1/8 o

Ivanshal [37]

6 pies.

If 8 teachers finish one whole pie, and they need to feed 47, then they need 6 pies with 8 slices each aka 48 slices total, there will be one slice leftover for the principal :D

6 0

1 year ago

The amount of oil used by a ship traveling at a uniform speed varies jointly with the distance and the square of the speed. The

frosja888 [35]

Answer:

Step-by-step explanation:

Joint variation has the equation

y = kxz

k is the constant of variation and needs to be solved for using the initial conditions, then filled in later to another equation related to the given info to solve for something else. We are given y = amount of oil used, x = distance traveled, z-squared is the speed. Our equation looks like this, to be exact:

$y=kxz^2$

Filling in with the initial conditions:

$34=k(60)(20)^2$ which gives us the

k = .0014166667

Now we need to find the amount of oil used, y, under other circumstances, but this time we have our k.

$y=(.0014166667)(32)(23)^2$

which gives us that the amount of oil used, when rounded to the tenths,

y = 24.0 barrels

7 0

2 years ago

Need help pleaseI was bad at math in school so lwant to learn

aleksklad [387]

The probability of an event is expressed as

$Pr(\text{event) =}\frac{Total\text{ number of favourable/desired outcome}}{Tota\text{l number of possible outcome}}$

Given:

$\begin{gathered} \text{Red}\Rightarrow2 \\ \text{Green}\Rightarrow3 \\ \text{Blue}\Rightarrow2 \\ \Rightarrow Total\text{ number of balls = 2+3+2=7 balls} \end{gathered}$

The probability of drwing two blue balls one after the other is expressed as

$Pr(\text{blue)}\times Pr(blue)$

For the first draw:

$\begin{gathered} Pr(\text{blue) = }\frac{number\text{ of blue balls}}{total\text{ number of balls}} \\ =\frac{2}{7} \end{gathered}$

For the second draw, we have only 1 blue ball left out of a total of 6 balls (since a blue ball with drawn earlier).

Thus,

$\begin{gathered} Pr(\text{blue)}=\frac{number\text{ of blue balls left}}{total\text{ number of balls left}} \\ =\frac{1}{6} \end{gathered}$

The probability of drawing two blue balls one after the other is evaluted as

$\begin{gathered} \frac{1}{6}\times\frac{2}{7} \\ =\frac{1}{21} \end{gathered}$

The probablity that none of the balls drawn is blue is evaluted as

$\begin{gathered} 1-\frac{1}{21} \\ =\frac{20}{21} \end{gathered}$

Hence, the probablity that none of the balls drawn is blue is evaluted as

$\frac{20}{21}$

8 0

11 months ago

A storage shed is to be built in the shape of a (closed) box with a square base. It is to have a volume of 150 cubic feet. The c

Alenkinab [10]

Answer:

$C(s) = 6s^2 + \dfrac{1500}{s}\\\text{where s is the side of base.}$

Step-by-step explanation:

We are given the following in the question:

A storage shed is to be built in the shape of a (closed) box with a square base.

Volume = 150 cubic feet

Let s be the edge of square base and h be the height.

Volume of cuboid =

$l\times b\times h$

where l is the length, b is the base and h is the height.

Volume of box =

$s^2h = 150\\\\h = \dfrac{150}{s^2}$

Area of base =

$\text{side}\times \text{side} = s^2$

Cost of concrete for the base = $4

Cost of base($) = $4s^2$

Area of roof =

$\text{side}\times \text{side} = s^2$

Cost of material for the roof = $2

Cost of roof ($) = $2s^2$

Area of 4 walls =

$4\times (sh)\\=4sh$

Cost of material for the side = $2.50

Cost of material of side($) =

$2.50\times 4s(\dfrac{150}{s^2})\\\\=\dfrac{1500}{s}$

Total cost

= Cost of base + Cost of 4 sides + Cost of roof

$C(s) = 4s^2 + \dfrac{1500}{s} + 2s^2\\\\C(s) = 6s^2 + \dfrac{1500}{s}$

is the required cost function.

5 0

3 years ago

Hey guys does anyone know how to lesson 26 Exit ticket 5.4 eureka math engage ny? The last problem: Larry spends half of his wor

Vesnalui [34]

Answer:

$\frac{1}{12}$ X

Step-by-step explanation:

Let X is the number of hours Larry works a day

Given: Larry spends half of his workday teaching piano lessons.

=> Number of hours he teaches piano a day is: $\frac{1}{2}$ X

As we know that, he has 6 students, so the fraction of his workday is spent with each student is:

$\frac{1}{2}$ X : 6

= $\frac{1}{12}$ X

Hope it will find you well during the time of isolation.

7 0

2 years ago

Read 2 more answers