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3 years ago

Help me :) I need help Algebra 2

Mathematics

1 answer:

Dmitrij [34]3 years ago

8 0

What is the question?

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Each patron pays an annual fee of $36 to the library. If the library collects $20,304 from the annual fee, how many patrons are

choli [55]

Answer:

564 patrons.

Step-by-step explanation:

20,304/36 = 564

5 0

2 years ago

What does arc BC equal?

Dmitrij [34]

Answer:

124

Step-by-step explanation:

take 146, add 90 then subtract that answer from 360

8 0

3 years ago

-4(3x-1)=12-8x and plz show how you got it

Inga [223]

Step 1: -4(3x-1) becomes -12x+4
step 2: -12x+4=12-8x
step 3: add 12x to both sides, 4=12+4x
step 4: subtract twelve from both sides -8=4x
step 5: divide by 4, x=-2

3 0

3 years ago

Read 2 more answers

Determine the equation of the circle graphed below.

sergij07 [2.7K]

Answer:

Equation = (x - 6 )² + ( y + 3 )² = 9

Step-by-step explanation:

The circle passes through ( 6, 0) and ( 6 , -6)

They are the coordinates of the diameter.

Using this we can find the centre of the circle.

Find the centre of the circle.

Centre of the circle is the mid- point of (6, 0) and ( 6, -6)

$Centre = (\frac{x_1+x_2}{2} , \frac{y_1 + y_2}{2})$

$=(\frac{6 + 6}{2}, \frac{0 + (-6)}{2})\\\\=(6, -3)$

Find the radius of the circle.

$Radius = \frac{Diameter }{2}$

Diameter is the distance between the points (6 , 0) and ( 6, - 6)

$Diameter = \sqrt{(x_2 - x_1)^2+ (y_2 - y_1)^2\\}$

$=\sqrt{(6-6)^2 + (-6 -0)^2}\\\\=\sqrt{0 + 36} \\\\= 6$

Therefore,

$Radius ,r = \frac{6}{2} = 3$

Standard equation of a circle:

$(x - a)^2 + (y - b)^2 = r^2 \ where \ (a , b) \ is \ the\ centre \ coordinates.$

Therefore , equation of the circle ;

$(x - 6)^2 + (y + 3)^2 = 3^2\\\\(x -6)^2 + (y + 3)^2 = 9$

6 0

3 years ago

Find the quotient of 2/5 and 4/5

Elis [28]

Answer:

10/20 or 1/2

Step-by-step explanation:

Heres a picture to explain:

7 0

2 years ago