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Galina-37 [17]
3 years ago
7

Solve for variable: 5z/8 – 1/3 = 2/5

Mathematics
1 answer:
Ksivusya [100]3 years ago
5 0

Answer: z= .6

Step-by-step explanation:

Numerator: When you do 5•.6, you get 3, and then 3-1 equals 2.

Denominator: 8 - 3 = 5.

Therefore you get 2/5 which makes z = .6

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Klio2033 [76]
What are you asking?


5 0
3 years ago
PLEASE HELP ME Determine the premiter of the figure . Use 3.14 for PI Round to the nearest tenth. Numbers are 10 in and 15in​
densk [106]

Answer:

5\pi+40

Step-by-step explanation:

perimeter of circle=2\pir

so 5 is r(radius)

so 10\pi, but since it’s semicircle, you have to divide by 2, so

5\pi

perimeter of rectangle=15+10+15 because you don’t count the inside, so that equals 40

so 5\pi+40

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2 years ago
Find the value of 3 to the power of -3 times 10 to the power of -3
nika2105 [10]

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8 0
3 years ago
Boat travel 27 miles in two hours how many miles travel in 1/2 hours
Sloan [31]

Answer:

6.75

Step-by-step explanation:

8 0
3 years ago
The area of the shaded segment is 100cm^2. Calculate the value of r.
Reil [10]
Hello, 

The formula for finding the area of a circular region is: A=  \frac{ \alpha *r^{2} }{2}

then:
A_{1} = \frac{80*r^{2} }{2}

With the two radius it is formed an isosceles triangle, so, we must obtain its area, but first we obtain the height and the base.

cos(40)= \frac{h}{r}  \\  \\ h= r*cos(40)\\ \\ \\ sen(40)= \frac{b}{r} \\ \\ b=r*sen(40)

Now we can find its area:
A_{2}=2* \frac{b*h}{2}  \\  \\ A_{2}= [r*sen(40)][r*cos(40)]\\  \\A_{2}= r^{2}*sen(40)*cos(40)

The subtraction of the two areas is 100cm^2, then:

A_{1}-A_{2}=100cm^{2} \\ (40*r^{2})-(r^{2}*sen(40)*cos(40) )=100cm^{2} \\ 39.51r^{2}=100cm^{2} \\ r^{2}=2.53cm^{2} \\ r=1.59cm

Answer: r= 1.59cm
7 0
3 years ago
Read 2 more answers
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