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3 years ago

Factor the equation. X2-15x+50=0

Mathematics

2 answers:

maw [93]3 years ago

8 0

Answer:

(x - 10)(x - 5)

Step-by-step explanation:

Step 1- Find 2 numbers that multiply to be 50.

10 × 5

-10 × -5

25 × 2

-25 × -2

All these multiply to get 50.

But the numbers must also add up to be -15.

Step 2- Find the 2 numbers that also add up to be -15.

10 + 5 = 15

-10 + -5 = -15

25 + 2 = 27

-25 + -2 = -27

The correct equation would be - 10 + -5

The 2 number you would use when you factor would be -10 and -5

Step 3- Write the equation

You can write the equation as (x - 10)(x - 5)

Or you can also write it as (x - 5)(x - 10)

Alekssandra [29.7K]3 years ago

3 0

Answer:

(x - 10)(x - 5)

Step-by-step explanation:

Well to factor X^2-15x+50

we need to find 2 numbers that multiply to get 50 and add to get -15.

-5 * -10 = 50

-5 + -10

x*x = x^2

Factored (x - 10)(x - 5)

<em>Hope this helps :)</em>

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sveticcg [70]

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Step-by-step explanation:

When a terminal side of an angle intersect the unit circle at

point (x , y), then:

The x-coordinate is equal to cosine the angle between the positive part of x-axis and the terminal side
The y-coordinate is equal to sine the angle between the positive part of x-axis and the terminal side
If x and y coordinates are positive, then the angle lies in the 1st quadrant
If x-coordinate is negative and y-coordinate is positive, then the angle lies in the 2nd quadrant
If x and y coordinates are negative, then the angle lies in the 3rd quadrant
If x-coordinate is positive and y-coordinate is negative, then the angle lies in the 4th quadrant

∵ The terminal ray of angle Ф intersects the unit circle at point $(\frac{-\sqrt{2} }{2},\frac{\sqrt{2} }{2})$

- According to the 1st and 2nd notes above

∴ cosФ = x-coordinate of the point

∴ sinФ = y-coordinate of the point

∵ The x-coordinate of the point is negative

∵ They-coordinate of the point is positive

- According the the 4th note above

∴ Angle Ф lies in the 2nd quadrant

∵ x-coordinate = $\frac{-\sqrt{2} }{2}$

∴ cosФ = $\frac{-\sqrt{2} }{2}$

∵ y-coordinate = $\frac{\sqrt{2} }{2}$

∴ sinФ = $\frac{\sqrt{2} }{2}$

- cotФ is the reciprocal of tanФ

∵ tanФ = sinФ ÷ cosФ

∴ cotФ = cosФ ÷ sinФ

∴ cotФ = $\frac{-\sqrt{2} }{2}$ ÷ $\frac{\sqrt{2} }{2}$

∴ cotФ = -1

The values of cosine Ф and cotangent Ф are $\frac{-\sqrt{2} }{2}$ and -1

Learn more:

You can learn more about the trigonometry function in brainly.com/question/4924817

#LearnwithBrainly

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