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Ad libitum [116K]
3 years ago
8

Find the percent of change from the original price of $184 to the sale price of $138.

Mathematics
1 answer:
Rzqust [24]3 years ago
7 0

Answer: 25%

Step-by-step explanation:

184-138= 46

184*.25=46

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1 year ago
Find the common difference of the arithmetic sequence.
kvv77 [185]

The common difference is 1/5 since the sequence gets progressively higher by 1/5

-2 + 1/5 = -9/5 or - 1 4/5

etc ..

4 0
3 years ago
DOMAIN:<br> RANGE<br> FUNCTION:<br><br> PLZZ HELP HURRYY‼️‼️‼️
GaryK [48]

Answer:

The input (domain) are usually on the left side of the circle.

Domain = [-2, 0, 3, 4, 6]

The output (range) are usually on the right side of the circle.

Range = [-3, -2, 0, 1, 2, 4]

Since the domain of 3 is pointing at two ranges (3, 4) and (3, -3), the x value repeats.

Functions do not have repeating x values.

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3 0
3 years ago
Read 2 more answers
Find 356*27+537*373-235*73=
sesenic [268]

Answer:

Using PEMDAS the answer would be 192758

Step-by-step explanation:

(356*27)+(537*373)-(235*73)=

9612+200301-17155=

Solve

192758

Happy learning!

--Applepi101

5 0
3 years ago
Solve the following congruence equations for X a) 8x = 1(mod 13) b) 8x = 4(mod 13) c) 99x = 5(mod 13)
xxMikexx [17]

Answer:

a) 5+13k  where k is integer

b) 20+13k where k is integer

c)12+13k where k is integer

Step-by-step explanation:

(a)

8x \equiv 1 (mod 13) \text{ means } 8x-1=13k.

8x-1=13k

Subtract 13k on both sides:

8x-13k-1=0

Add 1 on both sides:

8x-13k=1

I'm going to use Euclidean Algorithm.

13=8(1)+5

8=5(1)+3

5=3(1)+2

3=2(1)+1

Now backwards through the equations:

3-2=1

3-(5-3)=1

3-5+3=1

(8-5)-5+(8-5)=1

2(8)-3(5)=1

2(8)-3(13-8)=1

5(8)-3(13)=1

So compare this to:

8x-13k=1

We see that x is 5 while k is 3.

Anyways 5 is a solution or 5+13k is a solution where k is an integer.

b)

8x \equiv 4 (mod 13)

8x-4=13k

Subtract 13k on both sides:

8x-13k-4=0

Add 4 on both sides:

8x-13k=4

We got this from above:

5(8)-3(13)=1

If we multiply both sides by 4 we get:

8(20)-13(12)=4

So x=20 and 20+13k is also a solution where k is an integer.

c)

[tex]99x \equiv 5 (mod 13)[/tex

99x-5=13k

Subtract 13k on both sides:

99x-13k-5=0

Add 5 on both sides:

99x-13k=5

Using Euclidean Algorithm:

99=13(7)+8

13=8(1)+5

Go back through the equations:

13-8=5

13-(99-13(7))=5

8(13)-99=5

99(-1)+8(13)=5

Compare this to 99x-13k=5 and see that x=-1 or -1+13=12 or 12+13k is a solution where k is an integer.

8 0
3 years ago
Read 2 more answers
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