The LCD is basically the LCM of the denoenator so
to find LCM of exg 6 and 21, find factors and group
6=2 and 3 (one 2 and one 3)
21=3 and 7 (one 3 and one 7)
lcm=2 and 3 and 7 (include 6 and 21 in the number) (one 2 and one 3 and one 7)
LCM≈LCD
so
17.
denomenators are 2 and x^2
2=2
x^2=x times x
lcm=2 times x times x=2x^2
18.
denomenators are 6 and 9
6=2 and 3
9=3 and 3
LCM=2 times 3 times 3=18
19.
denomenators are z and 7z
z=z
7z=7 and z
lcm=7 times z=7z
20.
denomenators are 5b and 7b^3c
5b=5 and b
7b^3c=7 times b times b times b times c
LCM=7 times 5 times b times b times b times c=7b^3c=7cb^3
21. denomenator=5 and x+2
5=5
x+2=x+2
LCM=5 times (x+2)=5(x+2)=5x+10
22. denomenators are ab and b^2c
ab=a time b
b^2c=b times b times c
LCM=a times b times b times c=ab^2c=acb^2
23. demonenators are m+n and m-n
m+n=m+n
m-n=m-n
LCM=(m+n)(m-n)=m^2-n^2
24.denoenators are k and k^2-2
k=k
k^2-2=k^2-2
LCM=k times (k^2-2)=k^3-2k
Answer:
The (-3x-9)=27 and (-5x-2)=10
Step-by-step explanation:
Try it and see look In the corner
t=0, d=0 so ans B is wrong
t=0, dd/dt <0 as it is propelled downward so ans C is wrong
ang vel = 2
/ period
= 2 / 4.5
= 4 / 9
so D is the correct answer
0.0025 miles per second, 9/(60*60). Denominator is converting hours to seconds.
