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kolezko [41]
3 years ago
15

A tutor schedules either 30-minute sessions or 60-minute sessions with her students.Last week, the tutor gave 8 sessions which l

asted for a total of 7 hours. How many 60-minute sessions did the tutor give last week?
ANSWER THIS QUICKLY PLEASE! THANKS!
Mathematics
2 answers:
umka2103 [35]3 years ago
6 0
6 one hour sessions and 2 half hour sessions for a total of 8 sessions. Answer: 6
Mazyrski [523]3 years ago
5 0
The tutor gave 7 sessions that lasted 60 minutes last week.

7x60=420

420minutes in total, divided by 60min session = 7 sessions that lasted 60 minutes

I hope this helped, and you understand
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12 divided by 2 = 6 ounces = $1
20 divided by 3 = 6.66 ounces = 1

the first option should be the best option to get since its cheaper.

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Gavin needs to buy candy for the 11 students in his class plus himself. Gavin and each student will get one bag of candy. He use
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20=1.50(6)+2.00(4)

Step-by-step explanation:

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One eighth of the number of raisin bagels sold on Friday were sold on Saturday. How many raisin bagels were sold on Saturday? Th
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Answer:

The answer is 4.

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The answer is 4, 1/8 of 32 is 4.

4 Raisin Bagels were sold on Saturday

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T what point does the curve have maximum curvature? Y = 7ex (x, y) = what happens to the curvature as x → ∞? Κ(x) approaches as
Nookie1986 [14]

Formula for curvature for a well behaved curve y=f(x) is


K(x)= \frac{|{y}''|}{[1+{y}'^2]^\frac{3}{2}}


The given curve is y=7e^{x}


{y}''=7e^{x}\\ {y}'=7e^{x}


k(x)=\frac{7e^{x}}{[{1+(7e^{x})^2}]^\frac{3}{2}}


{k(x)}'=\frac{7(e^x)(1+49e^{2x})(49e^{2x}-\frac{1}{2})}{[1+49e^{2x}]^{3}}

For Maxima or Minima

{k(x)}'=0

7(e^x)(1+49e^{2x})(98e^{2x}-1)=0

→e^{x}=0∨ 1+49e^{2x}=0∨98e^{2x}-1=0

e^{x}=0  ,  ∧ 1+49e^{2x}=0   [not possible ∵there exists no value of x satisfying these equation]

→98e^{2x}-1=0

Solving this we get

x= -\frac{1}{2}\ln{98}

As you will evaluate {k(x})}''<0 at x=-\frac{1}{2}\ln98

So this is the point of Maxima. we get y=7×1/√98=1/√2

(x,y)=[-\frac{1}{2}\ln98,1/√2]

k(x)=\lim_{x\to\infty } \frac{7e^{x}}{[{1+(7e^{x})^2}]^\frac{3}{2}}

k(x)=\frac{7}{\infty}

k(x)=0







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A store owner has 17.25 lbs. of candy. If she puts the candy into 7.5 jars, how much candy will each jar contain? HELP PLEASEEE
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9.75

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