Answer:
F(d) = 30 + 0.50d
Step-by-step explanation:
Given
Charges = P8.00 ---- first 4 km
Additional = P0.50
Required
Write a function to address the scenario.
Represent the whole distance covered with d.
First,we need to determine the total charges for the first four hours.
Charges = 8.00 * 4
Charges = 32.00
Next, we determine the charges for additional distance.
Charges = 0.50 * (d - 4)
d - 4 is the remaining distance after the first 4.
Charges = 0.50d - 2
The function is then written as;
F(d) = 32 + 0.50d - 2
F(d) = 32 - 2 + 0.50d
F(d) = 30 + 0.50d
$16(4 shirts)= $64
5%=$64(0.05)=$3.20
Jamal's total is $67.20
Answer:
-1
Step-by-step explanation:
This all comes down to the substitution. I am assuming that (4x2) is meant to be 4x^2 so I will solve as that.
4(-2)^2 = 4(4) = 16
4(-2) = - 8
-2(3)^2 = -2(9) = -18
3(3) = 9
16-8-18+9= -1
Answer:
A, B and D
Step-by-step explanation:
A. The polynomial is a trinomial.
A trinomial refers to a polynomial with three terms. This option is correct.
B. The degree of the polynomial is 6.
Degree refers to the highest power in the polynomial. This option is correct.
C. The leading coefficient is 1
This is false. The leading coefficient is the coefficient of the variable bearing the degree of the polynomial. This is wrong.
D. Written in standard form, the polynomial is –2x6 + x5 + 3.
This is correct.
Answer:
a)0.08 , b)0.4 , C) i)0.84 , ii)0.56
Step-by-step explanation:
Given data
P(A) = professor arrives on time
P(A) = 0.8
P(B) = Student aarive on time
P(B) = 0.6
According to the question A & B are Independent
P(A∩B) = P(A) . P(B)
Therefore
& 
is also independent
= 1-0.8 = 0.2
= 1-0.6 = 0.4
part a)
Probability of both student and the professor are late
P(A'∩B') = P(A') . P(B') (only for independent cases)
= 0.2 x 0.4
= 0.08
Part b)
The probability that the student is late given that the professor is on time
= 
= 
= 0.4
Part c)
Assume the events are not independent
Given Data
P
= 0.4
=
= 0.4
= 0.4 x P
= 0.4 x 0.4 = 0.16
= 0.16
i)
The probability that at least one of them is on time
= 1-
= 1 - 0.16 = 0.84
ii)The probability that they are both on time
P
= 1 - 
= 1 - ![[P({A}')+P({B}') - P({A}'\cap {B}')]](https://tex.z-dn.net/?f=%5BP%28%7BA%7D%27%29%2BP%28%7BB%7D%27%29%20-%20P%28%7BA%7D%27%5Ccap%20%7BB%7D%27%29%5D)
= 1 - [0.2+0.4-0.16] = 1-0.44 = 0.56
