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BartSMP [9]
3 years ago
13

Jean transformed a point by using the rule (x,y) (x-6, y+8). The image point is (–4, 1). Which point is the pre-image?

Mathematics
2 answers:
zepelin [54]3 years ago
8 0

Answer: B, (2, -7).

Step-by-step explanation:  I got the question right on the quiz.

lubasha [3.4K]3 years ago
3 0
For this case we have the following transformation:
 (x, y) (x-6, y + 8)

 Using the transformation we have that the image is:
 (-4, 1)

 Therefore, making use of this information, we can find the coordinates of the pre-image
 We have then:
 x-6 = -4

 From here, we clear x:
 x = -4 + 6

x = 2
 On the other hand we have:
 y + 8 = 1

 From here, we clear y:
 y = 1-8

y = -7
 The coordinates of the pre-image is:
 (x, y) = (2, -7)

 Answer:
 
A point that is the pre-image is:
 
(x, y) = (2, -7)
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Answer:

D

Step-by-step explanation:

you can just find the value of y and try some number of x

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3 years ago
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8 0
3 years ago
Mathematics algebra sat
Leya [2.2K]

Hey there!

2(p + 1) + 8(p - 1) = 5p

2(p) + 2(1) + 8(p) + 8(-1) = 5p

2p + 2 + 8p - 8 = 5p

10p - 6 = 5p

SUBTRACT 5p to BOTH SIDES

10p - 6 - 5p = 5p - 5p

SIMPLIFY IT!

5p - 6 = 0

ADD 6 to BOTH SIDES

5p - 6 + 6 = 0 + 6

CANCEL out: -6 + 6 because it gives you 0

KEEP: 0 + 6 because it helps solve for the p-value

5p = 0 + 6

5p = 6

DIVIDE 5 to BOTH SIDES

5p/5 = 6/5

CANCEL out: 5/5 because it gives you 1

KEEP: 6/5 because gives you the result of the p-value

SIMPLIFY IT!

p = 6/5

Therefore, your answer is: p = 6/5

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8 0
2 years ago
Read 2 more answers
Please help me in this questions....​
Ivahew [28]

Part (i)

I'm going to use the notation T(n) instead of T_n

To find the first term, we plug in n = 1

T(n) = 2 - 3n

T(1) = 2 - 3(1)

T(1) = -1

The first term is -1

Repeat for n = 2 to find the second term

T(n) = 2 - 3n

T(2) = 2 - 3(2)

T(2) = -4

The second term is -4

<h3>Answers: -1, -4</h3>

==============================================

Part (ii)

Plug in T(n) = -61 and solve for n

T(n) = 2 - 3n

-61 = 2 - 3n

-61-2 = -3n

-63 = -3n

-3n = -63

n = -63/(-3)

n = 21

Note that plugging in n = 21 leads to T(21) = -61, similar to how we computed the items back in part (i).

<h3>Answer:  21st term</h3>

===============================================

Part (iii)

We're given that T(n) = 2 - 3n

Let's compute T(2n). We do so by replacing every copy of n with 2n like so

T(n) = 2 - 3n

T(2n) = 2 - 3(2n)

T(2n) = 2 - 6n

Now subtract T(2n) from T(n)

T(n) - T(2n) = (2-3n) - (2-6n)

T(n) - T(2n) = 2-3n - 2+6n

T(n) - T(2n) = 3n

Then set this equal to 24 and solve for n

T(n) - T(2n) = 24

3n = 24

n = 24/3

n = 8

This means 2n = 2*8 = 16. So subtracting T(8) - T(16) will get us 24.

<h3>Answer: 8</h3>
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