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liraira [26]
3 years ago
9

Determine if 25110 is divisible by 45​

Mathematics
2 answers:
vfiekz [6]3 years ago
7 0

Answer:

Yes: 558

Step-by-step explanation:

25110 ÷ 45​ = 558

Daniel [21]3 years ago
4 0

Answer:

25110 is divisible by 45

Step-by-step explanation:

25110 : 45 = 558

225

------

=261

  225

  ------

  = 360

     360

     ------

     = = =

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Krystal needs at least $130 to go on a trip. Her father has given her $45. Which equality could be used to determine e, the rema
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Evaluate the expression for the given values.
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Step-by-step explanation:

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On a multiple-choice exam with three possible answers for each of the five questions, what is the probability that a student wou
SOVA2 [1]

Answer:

The required probability is \frac{11}{243}.

Step-by-step explanation:

Consider the provided information.

On a multiple-choice exam with three possible answers for each of the five questions.

That means the Probability of guess being correct is = p=\frac{1}{3}

The Probability of guess being incorrect is = q=\frac{2}{3}

We need to find the probability that a student would get four or more correct answers just by guessing.

Let X represents the probability of being correct

P(X\geq4)=P(X=4)+P(X=5)

Use the binomial distribution: ^nC_r=\binom{n}{r}p^rq^{n-r}

P(X\geq4)=\binom{5}{4}(\frac{1}{3})^4(\frac{2}{3})^{1}+\binom{5}{5}(\frac{1}{3})^5(\frac{2}{3})^{0}

P(X\geq4)=5\times(\frac{1}{3})^4(\frac{2}{3})^{1}+(\frac{1}{3})^5\\\\P(X\geq4)=\frac{10}{243}+\frac{1}{243}\\\\P(X\geq4)=\frac{11}{243}

Hence, the required probability is \frac{11}{243}.

5 0
4 years ago
On a blue print every 1/4 inch is 1 ft what is the scale statement in the form of 1:x
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Answer:

1 inch: 4 ft

Step-by-step explanation:

We can use proportions to solve this problem.  Put the blue print size on the top and the real life size on the bottom.

1/4 inch         1 inch

-----------  = -------------

1 ft              x ft


Using cross products

1/4 * x = 1*1

Multiply each side by 4

4 * 1/4 *x = 4*1

x =4

1 inch: 4 ft


5 0
3 years ago
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