In order to solve this i'd have to know what x equals?? does it tell you?
Distribute 7 to both n and 1
7(n + 1) = 7n + 7
5n + 7 = 7n + 7 - 2n
Combine like terms
5n + 7 = 7n - 2n + 7
5n + 7 = 5n + 7
If you want to solve for n, subtract 7 from both sides
5n + 7 (-7) = 5n + 7 (-7)
5n = 5n
then divide 5 from both sides
5n/5 = 5n/5
n = n
Effectively, this equation is <em>unsolvable</em>
hope this helps
Y=12/x
12/2=6
12/4=3
12/8=1.5 or 3/2
12/12=1
Answer is b
Given:
1 set requires 4 couples 8 dancers.
Total number of people at a square dance = 250.
To find:
The greatest number of sets possible at the dance.
Solution:
We have,
Total people = 250
1 set = 8 people.
Number of possible sets cannot be a decimal or fraction value. So, approx. the value to the preceding integer.
Therefore, the number of possible sets at the dance is 31.
Answer:
20 m by 10 m
Step-by-step explanation:
let w be width and l be length , then
2(l + w) = 60 ( divide both sides by 2 )
l + w = 30 ( subtract w from both sides )
l = 30 - w → (1)
lw = 200 → (2)
Substitute l = 30 - w into (2)
w(30 - w) = 200 ← distribute parenthesis on left side
30w - w² = 200 ( subtract 200 from both sides )
30w - w² - 200 = 0 ( multiply through by - 1 )
w² - 30w + 200 = 0 ← in standard form
(w - 10)(w - 20) = 0 ← in factored form
Equate each factor to zero and solve for w
w - 10 = 0 ⇒ w = 10
w - 20 = 0 ⇒ w = 20
Substitute these values into (1)
l = 30 - 10 = 20
l = 30 - 20 = 10
dimensions of field is 20 m by 10 m
