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3 years ago

A length of 9 and a perimeter of 22

Mathematics

1 answer:

Bad White [126]3 years ago

4 0

Answer:

Width is 2 if that's what you were looking for.

Step-by-step explanation:

I'm guessing it's a rectangle and you want the width?

22-9-9=2w

2w=4

The width is 2

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Step-by-step explanation:

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2 years ago

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The image of the point (2, 1) under a translation is (5, -3). Find

Yanka [14]

Answer:

The coordinates of the image of the point (6,6) under the same translation is: (9, 2)

Hence, option C is correct.

Step-by-step explanation:

The image of the point (2, 1) under a translation is (5, -3).

It means when we horizontally move 3 units to the RIGHT i.e. adding 3 units to the x-coordinate and vertically move 4 units DOWN i.e. subtracting 4 units from the y-coordinate of the original point (2, 1), we get the coordinates of the image (5, -3).

Thus,

The rule of translation can be formulated such as:

(x, y) → (x + 3, y - 4)

(2, 1) → (2 + 3, 1 - 4) → (5, -3)

Thus,

Under the same rule of translation, we can determine the coordinates of the image of the point (6,6):

(x, y) → (x + 3, y - 4)

(6, 6) → (6 + 3, 6 - 4) → (9, 2)

Therefore, the coordinates of the image of the point (6,6) under the same translation is: (9, 2)

Hence, option C is correct.

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3 years ago

the sum of 2 consecutive integers is at most the difference between nine times the smaller and 5 times the larger

Reil [10]

<h2>Answer:</h2>

$x\geq 3 \ and \ x+1 \geq 4$

<h2>Step-by-step explanation:</h2>

The question in this problem is:

<em>The sum of 2 consecutive integers is at most the difference between nine times the smaller and 5 times the larger. What are the numbers?</em>

<em />

First of all, let's name the first variable $x$ which is the smaller number. Accordingly, the lager number will be $x+1$ given that those numbers are consecutive. On the other hand<em> at most </em>conveys the idea of an inequality, which is:

$\leq \\ which \ means \ less \ than$

So:

1. The sum of 2 consecutive integers can be written as:

$v+(v+1)$

2. Nine times the smaller and 5 times the larger can be written as:

$9v-5(v+1)$

Finally, the whole statement:

The sum of 2 consecutive integers is at most the difference between nine times the smaller and 5 times the larger:

$x+(x+1) \leq 9x-5(x+1) \\ \\ x+x+1\leq 9x-5x-5 \\ \\ 2x+1 \leq 4x-5 \\ \\ 6 \leq 2x \\ \\$

$x+(x+1) \leq 9x-5(x+1) \\ \\ x+x+1\leq 9x-5x-5 \\ \\ 2x+1 \leq 4x-5 \\ \\ 6 \leq 2x \\ \\ \frac{6}{2} \leq \frac{2x}{2} \\ \\ 3 \leq x \\ \\ x\geq 3 \\ \\ and \\ \\ x+1 \geq 4$

The two numbers are:

$x\geq 3 \ and \ x+1 \geq 4$

6 0

3 years ago