Answer:
the third option
Step-by-step explanation:
do you want an explanation?
Answer:
Step-by-step explanation:
Given that
Group Group One Group Two
Mean 26.00 23.00
SD 2.00 4.00
SEM 0.40 1.21
N 25 11
where group I represents female servers and group II male servers.
We have to calculate confidence interval for 90% for difference in means
The mean of Group One minus Group Two equals 3.00
df = 34
standard error of difference = 0.993
t critical = 2.034 for 90% df 34
Hence confid. interval at 90%
=Mean diff ±2.034 * std error of diff
= (0.98, 5.02)
Answer:
16
Step-by-step explanation:
The distance is given by
d = sqrt( (x2-x1) ^2 + ( y2-y1) ^2)
Since the x values are the same
d = sqrt( ( y2-y1) ^2)
d = sqrt( (( -6 - 10)^2))
d = sqrt((-16) ^2)
d = 16
We can also just find the number of squares between the points since the x value is the same.
10 - -6
10+6
16
8/10 is greater than 63/100, it is grater because when u change them into a percentage 8/10 is higher
