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GREYUIT [131]
4 years ago
9

John has to solve the equation 3x = 15. What should John do the the equation?

Mathematics
1 answer:
PSYCHO15rus [73]4 years ago
6 0

Answer:

or,3x=15

or,x=15/3

the value of x is 5,,

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SOMEONE PLEASE JUST ANSWER THIS FOR BRAINLIEST!!!
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ANSWER

P-G = 11{w}^{4} - 5 {w}^{2}  {z}^{2}   - 4z^{4}

EXPLANATION

The given polynomials are:

G =  - 3 {w}^{4}  + 2 {w}^{2}  {z}^{2}  + 5z^{4}

and

P = 8 {w}^{4}   - 3{w}^{2}  {z}^{2}  + z^{4}

We want to subtract these two polynomials.

P-G = 8 {w}^{4}   - 3{w}^{2}  {z}^{2}  + z^{4}  - (- 3 {w}^{4}  + 2 {w}^{2}  {z}^{2}  + 5z^{4} )

Expand the right hand side to obtain:

P-G = 8 {w}^{4}   - 3{w}^{2}  {z}^{2}  + z^{4}   + 3 {w}^{4}   -  2 {w}^{2}  {z}^{2}   -  5z^{4}

Group the similar terms:

P-G = 8 {w}^{4}  + 3 {w}^{4}- 3{w}^{2}  {z}^{2} -  2 {w}^{2}  {z}^{2}   -  5z^{4} + z^{4}

Combine the similar terms to get:

P-G = 11{w}^{4} - 5 {w}^{2}  {z}^{2}   - 4z^{4}

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Answer:

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Step-by-step explanation:

\sqrt[3]{9x^3y^4}

\sqrt[3]{9}\sqrt[3]{x^3}\sqrt[3]{y^4}

The \sqrt[3]{x^3} cancels out to become x:

\sqrt[3]{9}x\sqrt[3]{y^4}

Split the y^4=y*y^3

\sqrt[3]{9}x\sqrt[3]{y^3}\sqrt[3]{y^1}

\sqrt[3]{y^3} =y

xy\sqrt[3]{9} \sqrt[3]{y}

Put the cube root of y and cube root of 9 together:

xy\sqrt[3]{9y}

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Answer:

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