The second term of the arithmetic sequence is:
a₂= -9
<h3>
How to find the second term in the sequence?</h3>
Here we have an arithmetic sequence, such the the recursive formula is:
aₙ = aₙ₋₁ + 4
So to get each term, we need to add 4 to the previous one.
We know that the first term is:
a₁ = -13
Then the second term will be:
a₂ = a₁ + 4 = -13 + 4 = -9
Learn more about arithmetic sequences:
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The first answer is right
(x - 9) (x + 9)
It’s me again lol
Answer:
4
Step-by-step explanation:
This situation has two unknowns - the total number of half dollars and the total number of quarters. Because we have two unknowns, we will write a system of equations with two equations using the two unknowns.
- h+q=31 is an equation representing the total number of coins
- 0.50h+0.25q=11 is an equation representing the total value in money based on the number of coin. 0.50 and 0.25 come from the value of a half dollar and quarter individually.
We write the first equation in terms of q by subtracting it across the equal sign to get h=31-q. We now substitute this for h in the second equation.
0.50(31-q)+0.25q=11
15.5-0.50q+0.25q=11
15.5-0.25q=11
After simplifying, we subtract 15.5 across and divide by the coefficient of q.
-0.25q=-4.5
q=4
We now know of the 31 coins that 4 are quarters.
Answer:
A. 11.4
Step-by-step explanation:
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Data:
P = 7
r = 0.07
Calculation:

19x³ + (14x + 4x³)=
You can assume that there is a 1 in front of the parentheses, so you can distribute the one to each term in the parentheses.
19x³ + 1(14x+4x³)=
19x³ + 14x + 4x³=
Then combine like terms to get 23x³ + 14x.
So 19x³ + 14x + 4x³= 23x³ + 14x