Question

Simplify the cube root in simplest radical form. 9x374 Please help

Answer 1

Answer:

D. $xy\sqrt[3]{9y}$

Step-by-step explanation:

$\sqrt[3]{9x^3y^4}$

$\sqrt[3]{9}\sqrt[3]{x^3}\sqrt[3]{y^4}$

The $\sqrt[3]{x^3}$ cancels out to become x:

$\sqrt[3]{9}x\sqrt[3]{y^4}$

Split the $y^4=y*y^3$

$\sqrt[3]{9}x\sqrt[3]{y^3}\sqrt[3]{y^1}$

$\sqrt[3]{y^3} =y$

$xy\sqrt[3]{9} \sqrt[3]{y}$

Put the cube root of y and cube root of 9 together:

$xy\sqrt[3]{9y}$