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3 years ago

10

Simplify the cube root in simplest radical form. 9x374 Please help

1 answer:

algol [13]3 years ago

6 0

Answer:

D. $xy\sqrt[3]{9y}$

Step-by-step explanation:

$\sqrt[3]{9x^3y^4}$

$\sqrt[3]{9}\sqrt[3]{x^3}\sqrt[3]{y^4}$

The $\sqrt[3]{x^3}$ cancels out to become x:

$\sqrt[3]{9}x\sqrt[3]{y^4}$

Split the $y^4=y*y^3$

$\sqrt[3]{9}x\sqrt[3]{y^3}\sqrt[3]{y^1}$

$\sqrt[3]{y^3} =y$

$xy\sqrt[3]{9} \sqrt[3]{y}$

Put the cube root of y and cube root of 9 together:

$xy\sqrt[3]{9y}$

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Similarly, terminal side of angle 'b' lies in quadrant 2, sine of angle 'b' will be negative.

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