I’m afraid you can’t delete , unless if we report it or else there’s no other way
(You go from left to right)
(Dividend is 931, divisor is 7)
Step 1: Look for a number smaller than 9 that is divisible by 7. 7 is the only one which is smaller than 9 and is divisible by 7. Now that you know 7*1=7, you put 1 above 931 (Dividend)
Step 2: You subtract that number from the number in tens place. And bring the leftover down.
Step 3: You repeat Step 1 and 2 until either you get a remainder of 0 or the remainder in smaller than the divisor (in this case 7)
(Therefore 931/7=133, quotient=133, remainder=0)
^Hope this helps.
Answer:
Infinite solutions
Step-by-step explanation:
Simplify both sides, subtract 9x, and add 21x to both sides and you will get 0 = 0 so there is infinite solutions.
Answer:
x = 9.5
Step-by-step explanation:
Given
=
( cross- multiply )
3(4x - 6) = 4(2x + 5) ← distribute parenthesis on both sides
12x - 18 = 8x + 20 ( subtract 8x from both sides )
4x - 18 = 20 ( add 18 to both sides )
4x = 38 ( divide both sides by 4 )
x =
= 9.5