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Luba_88 [7]
3 years ago
8

Find the midpoint of the line segment joining the points P1 and P2.

Mathematics
2 answers:
Brums [2.3K]3 years ago
6 0

Answer:

M= (1, 7/2)

Step-by-step explanation:

Karolina [17]3 years ago
5 0

Answer:

M= (1, 7/2)

Step-by-step explanation:

M = midpoint

M= ((x1+x2)/2) , ((y1+y2)/2)

we have:

P1 = (4,2)

P2 = (-2,5)

x1= 4  y1= 2

x2= -2   y2= 5

we have:

M= ((4-2)/2) , ((2+5)/2)

M= (2/2 , 7/2)

M= (1, 7/2)

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SinA/sinB=2/√3 and cosA/cosB=1/√2 ,tan^2B=?​
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Answer:

3/8 tan²A

Step-by-step explanation:

sinB = √3/2 sinA and cos B= √2 cosA (from given)

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2 years ago
Explain how complex fractions can be used to solve problems involving ratios?
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Complex fractions are numbers in which the numerator and the denominator are both fractions. in this case, to solve the ratio, we can multiply the numerator fraction by the reciprocal of the denominator fraction. Another way is to solve the fraction separately and then divide eventually. 
8 0
3 years ago
What is the solution to the system of equations? 2x+4t=12
katen-ka-za [31]

Answer:

C. (8, -1)

Step-by-step explanation:

{y = ¼x - 3}

{2x + 4y = 12

2x + 4[¼x - 3] = 12

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3x - 12 = 12

+ 12 + 12

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3x = 24

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3 3

x = 8 [Plug this back into both equations above to get the y-coordinate of −1]; -1 = y

I am joyous to assist you anytime.

6 0
3 years ago
18 points - Qu. If 16 whole numbers factor into 120. You will see how 32 whole numbers factor into 1200 what does the same princ
alexandr402 [8]

Explanation:

<em>Your premise and conclusion are both incorrect</em>.

120 has the prime factorization ...

  120 = 2³ × 3 × 5

The exponents of the prime factors are {3, 1, 1}. The number of divisors of 120 is the product of the increments of these numbers: (3+1)(1+1)(1+1) = 4·2·2 = 16.

120 has 16 natural-number divisors

__

1200 has the same prime factor and two more: 2·5, so the factorization is ...

  1200 = 2⁴ × 3 × 5²

These exponents are {4, 1, 2} and the product of their increments is 5·2·3 = 30.

1200 has 30 natural-number divisors.

__

When a number is multiplied by 2, its number of natural-number divisors will be (n+1)/n times the previous number of divisors, where n is the increment of the exponent of 2 that is a factor of the original number.

For 120, 2^3 is the power of 2 that is a factor. So, multiplying the number by 2 multiplies the number of divisors by (4+1)/4 = 5/4.

240 will have 20 divisors versus the 16 that 120 has.

Likewise, multiplying this number (240) by 5 will multiply its number of divisors by (2+1)/(1+1) = 3/2, where 1 is the power of 5 that is a factor of 240.

1200 will have 20(3/2) = 30 divisors, versus the 20 that 240 has, or the 16 that 120 has.

__

<em>Summary</em>

The number of divisors of an integer is the product of the increments of the exponents of its prime factors.

_____

<em>For reference</em>

Here are the divisors of 120:

  1, 2, 3, 4, 5, 6, 8, 10, 12, 15, 20, 24, 30, 40, 60, 120

Here are the divisors of 240:

  1, 2, 3, 4, 5, 6, 8, 10, 12, 15, 16, 20, 24, 30, 40, 48, 60, 80, 120, 240

Here are the divisors of 1200:

  1, 2, 3, 4, 5, 6, 8, 10, 12, 15, 16, 20, 24, 25, 30, 40, 48, 50, 60, 75, 80, 100, 120, 150, 200, 240, 300, 400, 600, 1200

7 0
3 years ago
-0.9+28<br> ----<br> 6<br> help me solve the task <br>im a little lazy ​
Anvisha [2.4K]

Answer:

around 4.52.

Fraction form: 4\frac{52}{100}

Step-by-step explanation:

Brainliest?

7 0
3 years ago
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