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olasank [31]
3 years ago
6

at the winter grove amusement park you can purchase a season discount pass for $75 that will allow a $10 admission to the park a

ll season. If you do not purchase the discount pass that the parking mission is $35 determine the number of times you must visit the park with the pass that would equal the cost of paying full price
Mathematics
1 answer:
Oksana_A [137]3 years ago
8 0

Answer:

You can visit the park 3 times before the 2 options equal

Step-by-step explanation:

Day 1

75+10=85

35

Day 2

85+10=95

35+35=70

Day 3

95+10=105

70+35=105

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Answer:

12/30

Step-by-step explanation:

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5 0
2 years ago
Answer for a lot of points!
earnstyle [38]

Given :

  • ZC = 90°

  • CD is the altitude to AB.

  • \angleA = 65°.

To find :

  • the angles in △CBD and △CAD if m∠A = 65°

Solution :

In Right angle △ABC,

we have,

=> ACB = 90°

=> \angleCAB = 65°.

So,

=> \angleACB + \angleCAB+\angleZCBA = 180° (By angle sum Property.)

=> 90° + 65° + \angleCBA = 180°

=> 155° +\angleCBA = 180°

=> \angleCBA = 180° - 155°

=> \angleCBA = 25°.

In △CDB,

=> CD is the altitude to AB.

So,

=> \angle CDB = 90°

=> \angleCBD = \angleCBA = 25°.

So,

=> \angleCBD + \angleDCB = 180° (Angle sum Property.)

=> 90° +25° + \angleDCB = 180°

=> 115° + \angleDCB = 180°

=> \angleDCB = 180° - 115°

=> \angleDCB = 65°.

Now, in △ADC,

=> CD is the altitude to AB.

So,

=> \angleADC = 90°

=>\angle CAD =\angle CAB = 65°.

So,

=> \angleADC + \angleCAD +\angleDCA = 180° (Angle sum Property.)

=> 90° + 65° + \angleDCA = 180°

=> 155° +\angleDCA = 180°

=> \angleDCA = 180° - 155°

=> \angleDCA = 25°

Hence, we get,

  • \angleDCA = 25°
  • \angleDCB = 65°
  • \angleCDB = 90°
  • \angleACD = 25°
  • \angleADC = 90°.
7 0
3 years ago
2.16 (the 6 is repeating) as a fraction (no improper fractions)
serg [7]

Answer:

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Step-by-step explanation:

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True or false? Of the mean,median,na dmode the median will always be most affected by the outliers.
inn [45]
Im pretty sure its true.
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Leon created a scale drawing of the school library in his art class. In the scale drawing, the length of the library is 13 inche
drek231 [11]

Answer:

The scale that Leon used to create the scale drawing is 1:72.

Step-by-step explanation:

Given that Leon created a scale drawing of the school library in his art class, and in the scale drawing, the length of the library is 13 inches while the length of the actual library is 78 feet, to determine which scale did Leon use to create the scale drawing of the school library, the following calculation must be performed:

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