Answer:
200 students were in the program
Step-by-step explanation:
The parent should know how to figure ...
170/85% = total/100%
This is the same as ...
total = 170/0.85 = 200
200 students were in the program.
_____
<em>Critical Thinking</em>
There are three declarative statements here. <em>There is no question</em>. We have made up a question to answer.
Another possible answer to the non-question could be, "The parent can ask his student how many students were in the program."
Answer:
about 27 hours
actual number: 26.6666666667
Step-by-step explanation:
80 divided by 3
Answer:
x= −1
/2 or x=4
Step-by-step explanation:
This is ALGEBRA, equations, factoring and zero property. ok.. let's solve this step-by-step
2x^2−7x=4
<u>Step 1: Subtract 4 from both sides.
</u>
2x^2−7x<u>−4 </u>=4 <u>−4
</u>
2x^2−7x−4=0
<u>Step 2: Factor left side of equation.
</u>
(2x+1)(x−4)=0
<u>Step 3: Set factors equal to 0.
</u>
2x+1=0 or x−4=0
x= −1
/2 or x=4
(BTW, there are supposed to be two answers, it's factoring)
Sorry if the format is not clear, but I hope this helped (really feel you, algebra can be brain-striking)!! Please leave a comment, rating and/or mark as the brainliest-whichever you think I deserve! Thank You :)
<span>D. One hundred random students from the sixth grade is the best choice given!
</span><span>
Reasons why the other answers and not good choices.
A. The first 100 students from an alphabetical list of the entire school, is incorrect because his only concern is the 6th graders, by including everyone he would negatively skew the data.
B. The first 100 students from an alphabetical list of sixth graders, is incorrect because its unfair to those with names starting later in the alphabet.
C. One hundred random students from the entire school </span>is is better but still incorrect because his only concern is the 6th graders, <span>by including everyone he would again negatively skew the data.</span>
Using BEDMAS
a) 6+4(2+3)^2
6+4(5)^2 - Eliminate addition in bracket
6+4(25) - Execute the exponent
6+100 - Mulitplying
106 - Addition
b)(6+4)(2+3)
(10)(5) -Addition in BRACKETS done
50 - Mulipication
If you found that helpful please rate as "Brainiest" if not comment below :)