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Zielflug [23.3K]
4 years ago
10

URGENT!!!!!!!!!!!!!!!!!!!!!!!!!!!!! can some explain the math behind the Flower of Life

Mathematics
1 answer:
Free_Kalibri [48]4 years ago
6 0
Hey there! Help this fruit helps!

<span>The flower of life symbol represents important meaning to many throughout history. ... Leonardo da Vinci studied the Flower of Life's form and its mathematical properties. He drew the Flower of Life itself, as well as various components such as the Seed of Life.</span>
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A coat costs €240. In a sale the coat now costs 25% less. The price of the coat in the sale is?
Bad White [126]
Take 1/4 away from 240 so whats 1/4 of 240?
60
7 0
4 years ago
Read 2 more answers
(GIVING BRAINLIEST!!)
HACTEHA [7]

Answer:

c is correct

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Please Answer Asap!!! Write the equation based on the graph of the following base 2 logarithmic function:
Nadya [2.5K]

The graph of the logarithmic function that passes through (-2,-2) and (1,0) is \log_2(x+3)-2.

Suppose that the function is

f(x)=\log_2(x+c)+d

Then there are two observations that we must consider from the figure

  1. The graph must pass through (-2,-2) and (1,0)

So,

-2=\log_2(-2+c)+d

\implies -2+c=e^{-2-d} ...~...~(1)

And,

0=\log_2(1+c)+d\\\implies 1+c=e^{-d} ~...~...~(2)

Observe the figure given below we see that the graph of

\log_2(x) passes through (1,0) but does not pass through (-2,-2) and the graph is to the right of (-2,-2) hence, we need the graph to move left.

When we increase c the graph  \log_2(x+c)+d  moves left and

When we decrease d then the graph  \log_2(x+c)+d  moves down.

That makes the graph required to be   \log_2(x+3)-2.

Hence, the graph of the logarithmic function that passes through (-2,-2) and (1,0) is \log_2(x+3)-2.

Learn more about logarithms here-

brainly.com/question/20785664

#SPJ10

3 0
2 years ago
So sorry if im wasting your time its just that i need help plsssssss im gonna fail so badly so help?
kykrilka [37]
The ANSWER for this question is C.85
4 0
2 years ago
One-half the sum of two consecutive odd integers is −12. Find the smallest integer.
melisa1 [442]

Answer:

Step-by-step explanation:

Let the larger integer = 2x + 1

Let the second integer = 2x - 1

1/2 (2x + 1 + 2x - 1) = - 12               Combine the left

1/2(4x) = - 12                                  Combine 1/2 (4x)

2x = - 12                                         Divide by 2

2x/2 = - 12/2

x = - 6

2x + 1 = 2*-6 + 1 = -11

2x - 1 = 2*-6 - 1  = - 13

Check

-11 + - 13  = - 24

1/2(-24) = -12                               which checks.

3 0
3 years ago
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